我将文件中的一个双精度值添加到变量中并将其推入向量中，格式为 "338620.3478" ，然后我从向量中获取值，它只是得到 "338620"，因为它无法获得所有双精度价值。
那么如何获得像原始格式一样的完整双精度值呢？
编码：
struct Point {
double x, y;
bool operator <(const Point &p) const {
return x < p.x || (x == p.x && y < p.y);
}
};
ifstream iFile("griddata.dat"); //read a file (grid)
string line;
Point Grid; /
while(getline(iFile,line))
{
unsigned pos = line.find(",");//the symbol is used to separate X and Y
std::string strs = line.substr(0,pos); // get X
std::string strs2 = line.substr(pos+1); // get Y
Grid.x = atof(strs.c_str()); // get the first cooordinate X
Grid.y = atof(strs2.c_str()); // get the second cooordinate Y
// A list of coordinates of grid is stored into the vector gridPoints
gridPoints.push_back(Grid); // adding the points of grid to vector
}
int j;
for(j=0;j<gridPoints.size();j++)
{
//here i cannot get the full double value for gridPoints[j].x;
//....it just gets "338620"
}
文件格式（griddata.dat）：
338620.3478,6196150.566
谢谢！