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我正在使用 Apache Commons 电子邮件 API 尝试以下代码，它会在上下文中引发错误。有什么帮助吗？

import java.util.Properties;

import javax.mail.PasswordAuthentication;
import javax.mail.Session;

import org.apache.commons.mail.EmailException;
import org.apache.commons.mail.SimpleEmail;


public class email {

    /**
     * @param args
     * @throws EmailException 
     */
    public static void main(String[] args) throws EmailException {
        // TODO Auto-generated method stub
        Properties props = new Properties();
        props.put("mail.smtp.auth", "true");
        props.put("mail.smtp.starttls.enable", "true");
        props.put("mail.smtp.host", "smtp.gmail.com");
        props.put("mail.smtp.port", "587");
        Session session = Session.getInstance(props,
                  new javax.mail.Authenticator() {
                    protected PasswordAuthentication getPasswordAuthentication() {
                        return new PasswordAuthentication("email@gmail.com", "password");
                    }
                  });
SimpleEmail se = new SimpleEmail();
se.addTo("email@gmail.com");
se.setFrom("email@gmail.com");
se.setSubject("Test email");
se.setMsg("Hi there");
se.send();

    }

}

它引发以下错误。我应该在哪里/什么设置来克服这个问题？在这方面有什么帮助吗？

javax.naming.NoInitialContextException: Need to specify class name in environment or system property, or as an applet parameter, or in an application resource file:  java.naming.factory.initial
    at javax.naming.spi.NamingManager.getInitialContext(Unknown Source)
    at javax.naming.InitialContext.getDefaultInitCtx(Unknown Source)
    at javax.naming.InitialContext.getURLOrDefaultInitCtx(Unknown Source)
    at javax.naming.InitialContext.lookup(Unknown Source)
    at javax.xml.registry.samples.SimpleClient.doit(Unknown Source)
    at javax.xml.registry.samples.SimpleClient.main(Unknown Source)

4

1 回答 1

1

您正在混合javax.mail和Apache Commons 电子邮件。此代码应该适合您：

public static void main(String[] args) {
{
    try
    {
        Email se = new SimpleEmail();

        se.setHostName("smtp.googlemail.com");
        se.setSmtpPort(465);
        se.setAuthenticator(new DefaultAuthenticator("email@gmail.com", "password"));
        se.setSSLOnConnect(true);


        se.addTo("email@gmail.com");
        se.setFrom("email@gmail.com");
        se.setSubject("Test email");
        se.setMsg("Hi there");
        se.send();
    }
    catch(EmailException e) {
        System.out.println("Uh oh! It doesn't work!");
    }
}

更多信息 ：

Apache Commons 电子邮件用户指南

于 2013-05-28T12:50:25.173 回答