1

我目前正在编写一个需要传输一些文件才能工作的服务器客户端应用程序。我正在使用这种方法:

客户:

file_to_send = raw_input(">") 

try:
    f = open("./sent_files/" + file_to_send, "rb")
except IOError, e:
    print ">error: ", e
    break

data = xmlrpclib.Binary(f.read())

if s.receive_file(file_to_send, data):
    print ">file correctly sent"

服务器:

def receive_file(self, name, arg):                                        
    with open("./sampletest/"+name, "wb") as handle: 
        handle.write(arg.data)

但是我该如何做相反的事情(我的意思是从服务器向客户端发送文件)?

4

1 回答 1

7

只需像这样在服务器上编写一个函数:

def send_file(self, name):
  with open('./sampletest/' + name, 'rb') as handle:
    return handle.read()

并在客户端上调用它:

data = send_file(fileName)
with open('./received_files/' + fileName, 'wb') as handle:
  handle.write(data)
于 2013-05-28T12:20:38.017 回答