4 
declare @id int
declare @empid int
set @id = 0
declare @schedindate datetime
declare @ss nvarchar(100)
declare @indice nvarchar(2)
declare @FromDate datetime
declare @ToDate datetime
declare @TimeInR datetime
declare @TimeOutR datetime
set @FromDate = '2009-01-14'
set @ToDate = '2010-01-30'

Declare cc cursor for select distinct empid from ta_timecard where schedindate between @FromDate and @ToDate
open cc
fetch next from cc into @empid
while (@@fetch_status = 0)
begin
    set @id = @id + 1
    insert into ta_MonthlyAttendance (ID, EmpID) values (@id, @empid)

    declare cc2 cursor for select distinct schedindate, TimeInR, TimeOutR from ta_timecard where empid = @empid and schedindate between @FromDate and @ToDate
    open cc2
    fetch next from cc2 into @schedindate, @TimeInR
    while (@@fetch_status = 0)
    begin

        set @indice = cast(datediff(day, @fromdate, @schedindate) as nvarchar(4))
        set @TimeInR = (select TOP 1 ta_TimeCard.TimeInR from ta_TimeCard where (@schedindate between @FromDate and @ToDate) and EmpID=@empid)
        set @schedindate = (select TOP 1 ta_TimeCard.SchedInDate from ta_TimeCard where (@schedindate between @FromDate and @ToDate) and empid=@empid)
        set @ss = 'update ta_MonthlyAttendance set NOD ' + @indice  + ' = + dbo.ta_dayofweek('+ char(39) + convert(nvarchar(50), @schedindate, 102) + char(39) +' ) , TimeInR ' + @indice + ' =  + @TimeInR + where empid = ' + cast(@empid as nvarchar(20))
        execute sp_executesql @ss
        fetch next from cc2 into @schedindate, @TimeInR
end
close cc2
deallocate cc2
fetch next from cc into @empid
end
close cc
Deallocate cc

此代码在“从 cc2 获取下一个到 @schedindate，@TimeInR”行中出现错误，我的错在哪里？没找到。。谢谢。。

4

2 回答 2

6 
declare cc2 cursor for 
   select distinct schedindate, TimeInR, TimeOutR 
   from ta_timecard where empid = @empid 
    and schedindate between @FromDate and @ToDate
    open cc2
    fetch next from cc2 into @schedindate, @TimeInR

您正在选择schedindate, TimeInR, TimeOutR，但 into 语句只有@schedindate, @TimeInR

拉吉

于 2013-05-28T07:20:56.733 回答
1

试试这个——

DECLARE 
      @empid INT
    , @schedindate DATETIME
    , @ss NVARCHAR(100)
    , @indice NVARCHAR(2)
    , @FromDate DATETIME
    , @ToDate DATETIME
    , @TimeInR DATETIME
    , @TimeOutR DATETIME

SELECT 
      @FromDate = '20090114'
    , @ToDate = '20100130'

DECLARE @temp TABLE
(
      schedindate DATETIME
    , TimeInR VARCHAR(10)
    , TimeOutR VARCHAR(10)
    , empid INT
)
INSERT INTO @temp (schedindate, TimeInR, TimeOutR, empid)
SELECT DISTINCT
      schedindate
    , TimeInR
    , TimeOutR
    , empid 
FROM dbo.ta_timecard
WHERE schedindate BETWEEN @FromDate AND @ToDate

DECLARE @ids TABLE(id BIGINT IDENTITY(1,1), emp BIGINT)
INSERT INTO @ids (emp)
SELECT DISTINCT empid
FROM @temp

INSERT INTO dbo.ta_MonthlyAttendance(id, EmpID)
SELECT id, emp
FROM @ids

DECLARE cc CURSOR LOCAL FAST_FORWARD READ_ONLY FOR
    SELECT DISTINCT empid
    FROM @temp

OPEN cc
FETCH NEXT FROM cc INTO @empid

WHILE (@@fetch_status = 0) BEGIN

    SELECT
          @indice = CAST(DATEDIFF(DAY, @fromdate, t.SchedInDate) AS NVARCHAR(4))
        , @TimeInR = t.TimeInR
        , @schedindate = t.SchedInDate
    FROM @temp t
    WHERE empid = @empid

    SELECT @ss = 'update ta_MonthlyAttendance set NOD ' + @indice 
        + ' = + dbo.ta_dayofweek(' + CHAR(39) 
        + CONVERT(NVARCHAR(50), @schedindate, 102) + CHAR(39) + ' ) , TimeInR ' 
        + @indice + ' = ' + @TimeInR + ' where empid = ' + CAST(@empid AS NVARCHAR(20))

    EXEC sys.sp_executesql @ss

    FETCH NEXT FROM cc INTO @empid

END

CLOSE cc
DEALLOCATE cc
于 2013-05-28T10:16:08.030 回答