我想向我的 php 脚本发送一条简单的消息（NSString）。我正在尝试执行 POST 请求。我无法做到这一点，我不确定我做错了什么。有人可以告诉我我的错误吗？
谢谢！
PHP 代码
<?php
if($_POST['error'])
{
$date= time();
$error=$_POST['error'];
$message=$date." ".$error;
echo $message;
//Rest of code just writes to a log file
?>
---------------------
NSString *post =[[NSString alloc] initWithFormat:@"error=%@",serverError];
NSData *postData = [post dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES];
NSString *postLength = [NSString stringWithFormat:@"%d", [postData length]];
NSMutableURLRequest *request = [[[NSMutableURLRequest alloc] init] autorelease];
[request setURL:[NSURL URLWithString:@"http://mysite.com/error.php"]];
[request setHTTPMethod:@"POST"];
[request setValue:postLength forHTTPHeaderField:@"Content-Length"];
[request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"];
[request setHTTPBody:postData];
NSURLResponse *response;
NSError *err;
NSData *responseData = [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&err];
NSLog(@"responseData is %@", responseData);