3

我正在尝试阅读过去 14 天的 android 短信消息，但是似乎需要很长时间才能从光标中读出所有消息，因此我将其限制为似乎不按时间顺序排列的第 100 条消息。

任何关于有效查询 esms 数据以便仅提取联系人和消息的想法？

我的代码：

Uri uriSMSURISent = Uri.parse("content://sms/sent"); // get the sms data for sent
Cursor curSent = getContentResolver().query(uriSMSURISent, null, null, null,null);

    int i=0;
   while (curSent.moveToNext() && i<100) 
    {
            String from = curSent.getString(2);
            if(sentHashmap.containsKey(to))
            {
                String cumulativeMessage = sentHashmap.get(to); 
                sentHashmap.put(from, cumulativeMessage+ " " +curSent.getString(12));
            }
            else
                sentHashmap.put(from, curSent.getString(12));
i++
4

1 回答 1

6

我建议您使用 ContentResolver 查询仅获取您感兴趣的记录。您可以选择不同的列，指定 where 子句甚至排序..

http://developer.android.com/guide/topics/providers/content-provider-basics.html

// Queries the user dictionary and returns results 
mCursor = getContentResolver().query(
     UserDictionary.Words.CONTENT_URI,   // The content URI of the words table
     mProjection,                        // The columns to return for each row
     mSelectionClause                    // Selection criteria
     mSelectionArgs,                     // Selection criteria
     mSortOrder); // The sort order for the returned rows Table 2  shows how the arguments to


 query(Uri,projection,selection,selectionArgs,sortOrder) match an SQL
 SELECT statement:


// column names for above provider:
0: _id
1: thread_id
2: address
3: person
4: date
5: protocol
6: read   
7: status
8: type
9: reply_path_present
10: subject
11: body
12: service_center
13: locked

现在你只需要用一个好的 where 子句来查询它：

  long date = new Date(System.currentTimeMillis() - 14L * 24 * 3600 * 1000).getTime();
  Cursor curSent = getContentResolver().query(uriSMSURISent, null,"date" + ">?",new String[]{""+date},"date DESC");
于 2013-05-27T21:15:14.573 回答