python - Python 前十榜单

Question

list = ('Bob', 11, 333, 453.3, 'Ted', 15, 999, 345.5, 'Jeff', 22, 122, 434.7)

嗨，我正在尝试根据上述信息构建前 10 名列表。

第一个值：进球，第二个值：助攻第三个值：上场时间

在这种情况下，我希望能够找到总目标最高的用户，我希望得到以下结果：

1）杰夫：22 2）泰德：15 3）鲍勃：11

Answer 1

你应该在这里使用字典：

>>> lis = ('Bob', 11, 333, 453.3, 'Ted', 15, 999, 345.5, 'Jeff', 22, 122, 434.7)
>>> dic = { lis[i]: list(lis[i+1:i+4]) for i in xrange(0,len(lis),4)}
>>> dic
{'Bob':  [11, 333, 453.3],
 'Ted':  [15, 999, 345.5],
 'Jeff': [22, 122, 434.7]}

>>> sorted(dic,key = dic.get,reverse = True)
['Jeff', 'Ted', 'Bob']

# To get keys as well as values use dict.items()
>>> for k,v in sorted(dic.items(), key =lambda x:x[1] , reverse = True):
    print k,v[0]
...     
Jeff 22
Ted 15
Bob 11

Answer 2

>>> from operator import itemgetter
>>> data = ('Bob', 11, 333, 453.3, 'Ted', 15, 999, 345.5, 'Jeff', 22, 122, 434.7)
>>> for x in sorted(zip(*[iter(data)]*4), key=itemgetter(1), reverse=True):
        print x[0], x[1]


Jeff 22
Ted 15
Bob 11