我发现 SBCL 'do-symbols'(和循环)返回重复项。
测试环境:SBCL 1.1.4 x86 on Windows
首先,我们定义一些辅助函数:
;; compress from Ansi-Common-Lisp
(defun compress (x)
(labels ((rec (e x n)
(if (null x)
(if (= 1 n)
(list e)
(list (list e n)))
(if (eq e (car x))
(rec e (cdr x) (1+ n))
(cons (if (= 1 n)
e
(list e n))
(rec (car x)
(cdr x)
1))))))
(rec (car x) (cdr x) 1)))
(compress '(a a b c d d d))
;;=> ((A 2) B C (D 3))
;; This one can make the duplicate items visible:
(defun duplicates (list)
(remove-if-not #'listp (compress (sort list #'string<))))
(duplicates '(a a b c d d d))
;;=> ((A 2) (D 3))
;; This one use 'do-symbols' iterate each symbol in package, and check the
;; result
(defun test-pack-do-symbols (package)
(let (r)
(do-symbols (s package (duplicates r))
(push s r))))
当调用包装上的“test-pack-do-symbols”时:SB-MOP,你可以看到重复的项目
(test-pack-do-symbols :sb-mop)
;;=> ((ADD-METHOD 2) (ALLOCATE-INSTANCE 2) (BUILT-IN-CLASS 2) (CLASS 2)
;; (CLASS-NAME 2) (COMPUTE-APPLICABLE-METHODS 2) (ENSURE-GENERIC-FUNCTION 2) #'2
;; (GENERIC-FUNCTION 2) (MAKE-INSTANCE 2) (METHOD 2) (METHOD-COMBINATION 2)
;; (METHOD-QUALIFIERS 2) (REMOVE-METHOD 2) (STANDARD-CLASS 2)
;; (STANDARD-GENERIC-FUNCTION 2) (STANDARD-METHOD 2) (STANDARD-OBJECT 2) (T 2))
还有另一种方法来迭代包中的符号,使用强大的“循环”。
;; Now I define `test-pack-loop'
(defun test-pack-loop (package)
(duplicates (loop for s being each symbol in package
collect s)))
调用“test-pack-loop”时,您不会看到重复的项目。
(test-pack-loop :sb-mop)
;;=> NIL
但是,即使循环可能会在某些包上返回重复项,您可以使用以下代码查看 'test-pack-do-symbols' 和 'test-pack-loop' 之间的区别
(let (r1 r2)
(dolist (p (list-all-packages))
(when (test-pack-do-symbols p)
(push (package-name p) r1))
(when (test-pack-loop p)
(push (package-name p) r2)))
(print r1)
(print r2)
nil)
那么,这是一个错误,还是与标准一致?