c++ - 执行操作时处理元素到内存块的速度

Question

那么实际上为什么我的周期不停地工作？？？它应该进行大约 100 次迭代，但它不会停止，请帮助。我拿了 min_block_size 这是我缓存 1 级的 10%，而 max_block_size 这是我的 l2 缓存的 10%！

#include <iostream>
#include <Windows.h>
#include <time.h>
#include <fstream>
#define MIN_BLOCK_SIZE 13108
#define MAX_BLOCK_SIZE 104858
#define STEP 1024
using namespace std;

int main()
{
    setlocale(LC_CTYPE, "Russian");


    int i, j, c, b;
    clock_t c1, c2;
    int*p = (int*) malloc(MAX_BLOCK_SIZE);
    int tmp = 0;
    LARGE_INTEGER start, finish, freq;
    c1 = clock();
    int n = 0;
    for (b = 13108; b < 104858; b = +1024)
    {
        QueryPerformanceFrequency(&freq);
        QueryPerformanceCounter(&start);
        for (c = 0; c <= b; c += sizeof (int))
        {
            tmp += *(int*) ((int) p + c);
            *(int*) ((int) p + c) = tmp;
        }
        QueryPerformanceCounter(&finish);
        double time = (finish.QuadPart - start.QuadPart) / (double) freq.QuadPart;
        n++;
        cout << "Размер" << n << "блоков:" << (MIN_BLOCK_SIZE + 1024 * (n - 1)) << "KB" << endl;
        cout << "Время o6pаботки" << n << "блоков" << time * 1000000 << "мкс" << endl;
        cout << "время обработки одного елемента" << time * 1000000000 / (MIN_BLOCK_SIZE + 1024 * (n - 1)) << "наносек" << endl;
    }
    c2 = clock();
    cout << "All the time is" << c2 - c1 << "sec";
    cin.get();
    cin.get();
    return 0;
}

Answer 1

这一行：

for (b = 13108; b < 104858; b = +1024)

意味着一个永远运行的循环，因为b它被重置为+1024（没有添加 1024！）。大概你打算写：

for (b = 13108; b < 104858; b += 1024)