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我正在使用 Scrapy 抓取网站以获取所有页面，但我当前的代码规则仍然允许我获取不需要的 URL，例如“ http://www.example.com/some-article/comment-page- ”之类的评论链接1 " 除了帖子的主 URL。我可以在规则中添加什么来排除这些不需要的项目？这是我当前的代码：

from scrapy.contrib.spiders import CrawlSpider, Rule
from scrapy.contrib.linkextractors.sgml import SgmlLinkExtractor
from scrapy.item import Item

class MySpider(CrawlSpider):
    name = 'crawltest'
    allowed_domains = ['example.com']
    start_urls = ['http://www.example.com']
    rules = [Rule(SgmlLinkExtractor(allow=[r'/\d+']), follow=True), Rule(SgmlLinkExtractor(allow=[r'\d+']), callback='parse_item')]

    def parse_item(self, response):
        #do something
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1 回答 1

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SgmlLinkExtractor有一个名为 的可选参数deny，这将仅在允许正则表达式为真且拒绝正则表达式为假时匹配规则

来自文档的示例：

rules = (
        # Extract links matching 'category.php' (but not matching 'subsection.php')
        # and follow links from them (since no callback means follow=True by default).
        Rule(SgmlLinkExtractor(allow=('category\.php', ), deny=('subsection\.php', ))),

        # Extract links matching 'item.php' and parse them with the spider's method parse_item
        Rule(SgmlLinkExtractor(allow=('item\.php', )), callback='parse_item'),
    )

也许您可以检查 url 是否不包含单词comment？

于 2013-05-26T16:58:45.657 回答