1

我想从以下位置转换字符串（字幕）：

585
00:59:59,237 --> 01:00:01,105
- It's all right. - He saw us!

586
01:00:01,139 --> 01:00:03,408
I heard you the first time.

进入

59:59 - 没关系。- 他看见了我们！

01:00:01 我第一次听到你。

*我想要的是：如果时间在一个小时内，去掉“00：”前缀，如果时间大于1小时，则保留它*

我的正则表达式是：

pat = re.compile(r"""
    #\s*                    # Skip leading whitespace
    \d+\s                   # remoe lines contain only numbers
    ((?:(?:00)|(?P<hour>01)):(?P<time>\d{2}:\d{2})[,0-9->]+.*)[\r\n]+(?P<content>.*)[\r\n]+
    """, 
    re.VERBOSE)
data = pat.sub(r"\g<hour>\g<time> \g<content>", data)

它仅在\g<hour>不使用 ' ' 时才有效。谁能帮我？

4

2 回答 2

2

我想，这就是你要找的：

import re

s = """
585
00:59:59,237 --> 01:00:01,105
- It's all right. - He saw us!

586
01:00:01,139 --> 01:00:03,408
I heard you the first time.
"""

for line in re.findall(r'(\d+:)(\d+:\d+)(?:.*\n)(.*)', s):
    if line[0] == '00:':
        print ' '.join(line[1:])
    else:
        print ' '.join([''.join(line[0:2]), line[2]])

输出：

# 59:59 - It's all right. - He saw us!
# 01:00:01 I heard you the first time.
于 2013-05-26T13:59:28.127 回答
1

只是为了提供非重新方法（应该更快）：

a = """585
00:59:59,237 --> 01:00:01,105
- It's all right. - He saw us!

586
01:00:01,139 --> 01:00:03,408
I heard you the first time."""

for i, x in enumerate(a.split('\n')):
    m = i % 4
    if m == 0:
        continue
    elif m == 3:
        continue
    elif m == 1:
        print x[:x.find(":", x.find(":") + 1)],
    elif m == 2:
        print x
于 2013-05-26T14:20:41.143 回答