我最近有同样的问题。我将计数错误的想法与 Yann Trevin 提到的 Assert.Multiple 结合到 IEnumberable 的扩展方法中,它让我可以执行以下操作:
[Test]
public void TestEvenNumbers()
{
int[] numbers = new int[] { 2, 4, 12, 22, 13, 42 };
numbers.AssertAll((num) => Assert.That((num % 2) == 0, "{0} is an odd number", num));
}
这导致 NUnit 输出:
TestEvenNumbers:
5 of 6 tests passed; 0 inconclusive
FAILED: 13: 13 is an odd number
Expected: True
But was: False
Expected: 6
But was: 5
OP问题的解决方案是:
[Test]
public void TestSelect()
{
ids.AssertAll(CheckStoredProcedures);
}
private void CheckStoredProcedures(Id id)
{
DataTable old = Database.call("old_stored_proc",id);
DataTable new_ = Database.call("new_stored_proc",id);
Assert.AreEqual(old.Rows[0]["column"], new_.Rows[0]["column"]);
}
这是扩展方法(请注意,为了与 Linq 术语保持一致,我使用了“All”而不是“Multiple”):
using System;
using System.Text;
using System.Collections.Generic;
using NUnit.Framework;
public static class NUnitExtensions
{
public static void AssertAll<T>(this IEnumerable<T> objects, Action<T> test)
{
int total = 0;
int passed = 0;
int failed = 0;
int inconclusive = 0;
var sb = new StringBuilder();
foreach (var obj in objects)
{
total++;
try
{
test(obj);
passed++;
}
catch (InconclusiveException assertion)
{
inconclusive++;
string message = string.Format("INCONCLUSIVE: {0}: {1}", obj.ToString(), assertion.Message);
Console.WriteLine(message);
sb.AppendLine(message);
}
catch (AssertionException assertion)
{
failed++;
string message = string.Format("FAILED: {0}: {1}", obj.ToString(), assertion.Message);
Console.WriteLine(message);
sb.AppendLine(message);
}
}
if (passed != total)
{
string details = sb.ToString();
string message = string.Format("{0} of {1} tests passed; {2} inconclusive\n{3}", passed, total, inconclusive, details);
if (failed == 0)
{
Assert.Inconclusive(message);
}
else
{
Assert.AreEqual(total, passed, message);
}
}
}
}