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I'd like to make a force layout with two types of nodes : type 1 stay in the center, and type 2 move in the periphery. There are links between type 1 and type 2, so the graph should stay together.

I imagine that i can do that with fixing the gravity positive for type 1 node and negative for type two :

  force.gravity(function(d){return (d.type=='pers')?10:-15})

but gravity seems to be a one for all parameter. Is there other way or can i change that to make the gravity parameter node dependent ? Or a completely different way to achieve this ?

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2 回答 2

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我尝试了一段时间，结果它也没有任何效果。如果您查看代码，似乎重力无法发挥作用：

比较 .charge() 和 linkStrength()：

force.linkStrength = function(x) {
  if (!arguments.length) return linkStrength;
  linkStrength = typeof x === "function" ? x : +x;
  return force;
};
force.charge = function(x) {
  if (!arguments.length) return charge;
  charge = typeof x === "function" ? x : +x;
  return force;
};

到.gravity()：

force.gravity = function(x) {
  if (!arguments.length) return gravity;
  gravity = +x;
  return force;
};

我不确定其他地方是否有进一步的限制，但如果你将重力传递给一个函数，它将不知道如何处理它。

于 2013-05-25T13:48:00.857 回答
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电荷是力的属性，而不是节点的属性。您可以对每个节点收取不同的费用。节点带有负电荷，因此它们被“重力”吸引并被其他节点排斥。如果您为类型 1 的节点设置较大（幅度）的电荷，而为类型 2 的节点设置较小的电荷，您可能会达到预期的效果。

Mike Bostock 的这次演讲解释并展示了不同的力配置：

于 2013-05-25T16:39:21.413 回答