我有以下表格:
CREATE TABLE element (
element_id serial PRIMARY KEY,
local_id integer,
name varchar,
CONSTRAINT fk_element_local_id FOREIGN KEY (local_id)
REFERENCES local (local_id) MATCH SIMPLE
ON UPDATE NO ACTION ON DELETE NO ACTION
);
CREATE TABLE local (
local_id serial PRIMARY KEY,
parent_id integer,
name varchar,
CONSTRAINT fk_local_parent_id_local_id FOREIGN KEY (parent_id)
REFERENCES local (local_id) MATCH SIMPLE
ON UPDATE CASCADE ON DELETE SET NULL
);
CREATE TABLE category (
category_id serial PRIMARY KEY,
name varchar
);
CREATE TABLE action (
action_id serial PRIMARY KEY,
local_id integer,
category_id integer,
CONSTRAINT fk_action_local_id FOREIGN KEY (local_id)
REFERENCES local (local_id) MATCH SIMPLE
ON UPDATE NO ACTION ON DELETE NO ACTION,
CONSTRAINT fk_action_element_id FOREIGN KEY (element_id)
REFERENCES element (element_id) MATCH SIMPLE
ON UPDATE NO ACTION ON DELETE NO ACTION
);
我想从一个动作中选择所有元素。如果元素的本地是动作的本地的后代,它也应该出现。
例子:
表local
:
|local_id | parent_id | name |
|---------+-----------+------|
|1 |NULL |A |
|2 |1 |B |
|3 |1 |C |
|4 |3 |D |
|5 |NULL |E |
|6 |5 |F |
|_________|___________|______|
表category
:
| category_id | name |
|-------------+------|
|1 |A |
|2 |B |
|2 |C |
|_____________|______|
表element
:
|element_id | local_id | name | category_id |
|-----------+----------+------+-------------|
|1 |1 |A | 1 |
|2 |2 |B | 2 |
|3 |2 |C | 1 |
|4 |4 |D | 2 |
|5 |5 |E | 2 |
|6 |6 |F | 1 |
|7 |6 |G | 1 |
|___________|__________|______|_____________|
表action
:
|action_id | local_id | category_id |
|----------+----------+-------------|
| 1 | 1 | 2 |
| 2 | 3 | 1 |
| 3 | 5 | 1 |
| 4 | 6 | 1 |
|__________|__________|_____________|
我想要的查询结果:
CASE: action_id = 1
return: element_id: 2,4
CASE: action_id = 2
return: element_id: null
CASE: action_id = 3
return: element_id: 6,7
我已经创建了一个函数,它返回包括实际节点在内的所有后代,但由于调用函数数千次时的性能,我遇到了困难。我的功能如下所示:
CREATE OR REPLACE FUNCTION fn_local_get_childs(_parent_id integer)
RETURNS SETOF integer AS
$BODY$
DECLARE
r integer;
BEGIN
FOR r IN SELECT local_id FROM local WHERE local_id IN (
(WITH RECURSIVE parent AS
(
SELECT local_id , parent_id from local WHERE local_id = _parent_id
UNION ALL
SELECT t.local_id , t.parent_id FROM parent
INNER JOIN local t ON parent.local_id = t.parent_id
)
SELECT local_id FROM parent
)
)
LOOP
RETURN NEXT r;
END LOOP;
RETURN;
END;
$BODY$
LANGUAGE plpgsql VOLATILE
COST 100
ROWS 1000;
我的超慢查询如下所示:
select e.element_id, a.action_id
from action a
join element e on (
e.local_id=any(select fn_local_get_childs(a.local_id)) AND
e.category_id=a.category_id)
有没有办法在单个查询中组合函数中使用的递归?