0 
mysql> SELECT * FROM main_table;
+--------+----------+--------+
| id_book | id_author      |description |
+--------+----------+--------+
| 1           | 101     |   I love cat |
+--------+----------+--------+

mysql> SELECT * FROM author;
+---------+-----------+
|  id_author | name_author |
+---------+-----------+
| 101     | Dr Sent     |
+---------+-----------+

mysql> SELECT * FROM book;
+--------+---------+
| id_book | name_book |
+--------+---------+
|      1 |     cat |
+--------+---------+

你好，我还是 PHP 的新手，现在我对 PHP 和 MySQL 有点困惑。我有一个与我在数据库中的一个表相关的下拉列表。

首先我的系统出现一个列表作者姓名的页面，用户将能够选择哪个用户喜欢。

 JK ROWLING 
 DR SEUSS <-- author_name
 ROAD DAHL

接下来，它将转到一个新页面并有一个选择（列表/菜单），其中显示了一个书名列表。我可以从数据库中检索下拉列表，但我的问题是当我在下拉列表中选择一本书名称时，它会显示所有书籍描述并且无法选择正确的描述。

这是我的编码，以使其更清晰

$currentPage = $_SERVER["PHP_SELF"];

mysql_select_db($database_config, $config);
$query_Recordset1 = "SELECT * FROM book ORDER BY name_book ASC";
$Recordset1 = mysql_query($query_Recordset1, $config) or die(mysql_error());
$row_Recordset1 = mysql_fetch_assoc($Recordset1);
$totalRows_Recordset1 = mysql_num_rows($Recordset1);

$maxRows_Recordset2 = 1;
$pageNum_Recordset2 = 0;
if (isset($_GET['pageNum_Recordset2'])) {
  $pageNum_Recordset2 = $_GET['pageNum_Recordset2'];
}
$startRow_Recordset2 = $pageNum_Recordset2 * $maxRows_Recordset2;

$colname_Recordset2 = "-1";
if (isset($_GET['id_book'])) {
  $colname_Recordset2 = $_GET['id_book'];
}
mysql_select_db($database_config, $config);
$query_Recordset2 = sprintf("SELECT * FROM main_table WHERE id_book = %s ORDER BY description ASC", GetSQLValueString($colname_Recordset2, "int"));
$query_limit_Recordset2 = sprintf("%s LIMIT %d, %d", $query_Recordset2, $startRow_Recordset2, $maxRows_Recordset2);
$Recordset2 = mysql_query($query_limit_Recordset2, $config) or die(mysql_error());
$row_Recordset2 = mysql_fetch_assoc($Recordset2);

if (isset($_GET['totalRows_Recordset2'])) {
  $totalRows_Recordset2 = $_GET['totalRows_Recordset2'];
} else {
  $all_Recordset2 = mysql_query($query_Recordset2);
  $totalRows_Recordset2 = mysql_num_rows($all_Recordset2);
}
$totalPages_Recordset2 = ceil($totalRows_Recordset2/$maxRows_Recordset2)-1;

$queryString_Recordset2 = "";
if (!empty($_SERVER['QUERY_STRING'])) {
  $params = explode("&", $_SERVER['QUERY_STRING']);
  $newParams = array();
  foreach ($params as $param) {
    if (stristr($param, "pageNum_Recordset2") == false && 
        stristr($param, "totalRows_Recordset2") == false) {
      array_push($newParams, $param);
    }
  }
  if (count($newParams) != 0) {
    $queryString_Recordset2 = "&" . htmlentities(implode("&", $newParams));
  }
}
$queryString_Recordset2 = sprintf("&totalRows_Recordset2=%d%s", $totalRows_Recordset2, $queryString_Recordset2);
4

2 回答 2

0

尝试这个.........

SELECT 
    a.*, b.*, c.* 
FROM main_table a 
    inner join author b on a.id_author = b.id_author 
    inner join book c on a.id_book = c.id_book
于 2013-05-24T11:58:17.783 回答
0

首先，我建议使用AJAX并在选择项目时保持在同一页面上。通过这种方式，您可以将不同输入框的代码分开，最终看起来会更好。

要回答您的问题，您应该运行以下 mySQL 的 SQL 语句以获得您所要求的内容：

SELECT MAT.*,AUT.name_author, BOO.name_book
FROM main_table AS MAT, author AS AUT, book AS BOO
WHERE (MAT.id_book=BOO.id_book AND MAT.id_author=AUT.id_author) AND MAT.id_author=101
ORDER BY MAT.id_author, MAT.id_book;
您可以在此处 找到上述人员的 SQL Fiddle 代码。您可以更新WHERE子句中的“过滤”以按另一个表的作者 ID 或书籍 ID 进行过滤

于 2013-05-24T11:58:50.927 回答