对于这类问题,C# 或其他一些应用层解决方案可能是最好的方法。
但是可以用 SQL 来做,虽然有点复杂。
递归 CTE 的第一部分将采用 OrderID = 1 和 InvID =1 并对其进行计算,导致LeftInLot
> 0 或LeftToServe
> 0。
第二部分现在需要根据第一部分的结果使用两种不同的逻辑,这是通过子查询来完成的接着说。
它看起来像这样:
;WITH CTE_Orders AS
(
SELECT *, ROW_NUMBER() OVER (PARTITION BY Item ORDER BY OrderID) AS RN
FROM dbo.Orders
)
, CTE_Inventory AS
(
SELECT *, ROW_NUMBER() OVER (PARTITION BY Item ORDER BY InvID) AS RN
FROM dbo.Inventory
)
, CTE AS
(
SELECT o.RN AS OrderRN,
inv.RN AS InvRN,
OrderID ,
o.Item ,
o.Quantity AS OrderedQuantity ,
InvID ,
Lot ,
inv.Quantity AS InvQuantity,
CASE WHEN inv.Quantity - o.Quantity > 0 THEN o.Quantity ELSE inv.Quantity END AS ServedQuantity ,
CASE WHEN inv.Quantity - o.Quantity > 0 THEN 0 ELSE o.Quantity - inv.Quantity END AS LeftToServe,
CASE WHEN inv.Quantity - o.Quantity > 0 THEN inv.Quantity - o.Quantity ELSE 0 END AS LeftInLot
FROM CTE_Orders o
INNER JOIN CTE_Inventory inv ON o.Item = inv.Item
--WHERE OrderID = 1 AND InvID = 1
WHERE o.RN =1 AND inv.RN = 1
UNION ALL
SELECT CASE WHEN c1.LeftInLot <=0 THEN c1.OrderRN ELSE c2.OrderRN END AS OrderRN
,CASE WHEN c1.LeftInLot <=0 THEN c2.InvRN ELSE c1.InvRN END AS InvRN
,CASE WHEN c1.LeftInLot <=0 THEN c1.OrderID ELSE c2.OrderID END AS OrderID
,CASE WHEN c1.LeftInLot <=0 THEN c1.Item ELSE c2.Item END AS Item
,CASE WHEN c1.LeftInLot <=0 THEN c1.OrderedQuantity ELSE c2.OrderedQuantity END AS OrderedQuantity
,CASE WHEN c1.LeftInLot <=0 THEN c2.InvID ELSE c1.InvID END AS InvID
,CASE WHEN c1.LeftInLot <=0 THEN c2.Lot ELSE c1.Lot END AS Lot
,CASE WHEN c1.LeftInLot <=0 THEN c2.InvQuantity ELSE c1.LeftInLot END AS InvQuantity
,CASE WHEN CASE WHEN c1.LeftInLot <=0 THEN c2.InvQuantity ELSE c1.LeftInLot END - CASE WHEN c1.LeftInLot <=0 THEN c1.LeftToServe ELSE c2.OrderedQuantity END > 0
THEN CASE WHEN c1.LeftInLot <=0 THEN c1.LeftToServe ELSE c2.OrderedQuantity END
ELSE CASE WHEN c1.LeftInLot <=0 THEN c2.InvQuantity ELSE c1.LeftInLot END
END AS ServedQuantity
,CASE WHEN CASE WHEN c1.LeftInLot <=0 THEN c2.InvQuantity ELSE c1.LeftInLot END - CASE WHEN c1.LeftInLot <=0 THEN c1.LeftToServe ELSE c2.OrderedQuantity END > 0
THEN 0
ELSE CASE WHEN c1.LeftInLot <=0 THEN c1.LeftToServe ELSE c2.OrderedQuantity END - CASE WHEN c1.LeftInLot <=0 THEN c2.InvQuantity ELSE c1.LeftInLot END
END AS LeftToServe
,CASE WHEN CASE WHEN c1.LeftInLot <=0 THEN c2.InvQuantity ELSE c1.LeftInLot END - CASE WHEN c1.LeftInLot <=0 THEN c1.LeftToServe ELSE c2.OrderedQuantity END > 0
THEN CASE WHEN c1.LeftInLot <=0 THEN c2.InvQuantity ELSE c1.LeftInLot END - CASE WHEN c1.LeftInLot <=0 THEN c1.LeftToServe ELSE c2.OrderedQuantity END
ELSE 0
END AS LeftInLot
FROM CTE c1
INNER JOIN
(
SELECT o2.RN AS OrderRN,
inv2.RN AS InvRN,
InvID ,
Lot ,
inv2.Item ,
inv2.Quantity AS InvQuantity,
OrderID ,
o2.Quantity AS OrderedQuantity
FROM
CTE_Inventory inv2
INNER JOIN CTE_Orders o2 ON inv2.Item = o2.Item
) c2
ON c1.Item = c2.Item AND
((c2.InvRN = c1.InvRN + 1 AND c2.OrderRN = c1.OrderRN AND c1.LeftInLot <= 0 ) OR (c2.OrderRN = c1.OrderRN + 1 AND c2.InvRN = c1.InvRN AND c1.LeftInLot>0))
)
SELECT * FROM CTE
ORDER BY item,OrderID
SQLFiddle 演示 - 旧
SQLFiddle 演示 - 已修复
PS:因为你不能真正依赖它OrderID
并且InvID
是没有任何间隙的连续值 - 就像我的例子假设( )一样,应该做c2.OrderID = c1.OrderID + 1
额外的复杂性。ROW_NUMBER
(固定的)
编辑:
更新了处理多个项目的解决方案。开始时有几个 CTE 来计算 ROW_NUMBERS 为项目分区并在 JOIN 中使用这些而不是 ID。