2

我似乎无法绕开自定义对话框。我尝试了很多变化，但到目前为止没有运气。

这是我当前用于对话框的 xml：

<?xml version="1.0" encoding="utf-8"?>

<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
              android:id="@+id/edit_name"
              android:layout_width="wrap_content" 
              android:layout_height="wrap_content"
              android:layout_gravity="center" 
              android:orientation="vertical"  >

    <TextView
            android:id="@+id/Word"
            android:text="Word?"
            android:layout_width="wrap_content"
            android:layout_height="wrap_content"
            android:layout_gravity="left|center_vertical"/>

    <EditText
            android:layout_height="100dp"
            android:layout_width="match_parent"
            android:id="@+id/lookupWordEdit"
            android:inputType="text"/>
</RelativeLayout>

这是代码：

public class LookupWordDialogFragment extends DialogFragment {
    private EditText mEditText;

    public LookupWordDialogFragment() {
        // Empty constructor required for DialogFragment
    }

    public interface LookupWordDialogListener {
        void onFinishEditDialog(String inputText);
    }


    @Override
    public Dialog onCreateDialog(Bundle savedInstanceState) {
        AlertDialog.Builder builder = new AlertDialog.Builder(getActivity());
        // Get the layout inflater
        LayoutInflater inflater = getActivity().getLayoutInflater();
        final EditText lookupWordEdit = (EditText)getActivity().findViewById(R.id.lookupWordEdit);

        // Inflate and set the layout for the dialog
        // Pass null as the parent view because its going in the dialog layout
        builder.setView(inflater.inflate(R.layout.dialog_lookupword, null))
                // Add action buttons
                .setPositiveButton("OK", new DialogInterface.OnClickListener() {
            @Override
            public void onClick(DialogInterface dialog, int id) {
                // Return input text to activity

                LayoutInflater inflater = getActivity().getLayoutInflater();
                final EditText lookupWordEdit = (EditText)getActivity().findViewById(R.id.lookupWordEdit);

                LookupWordDialogListener activity = (LookupWordDialogListener) getActivity();
                activity.onFinishEditDialog(lookupWordEdit.getText().toString());
            }
        })
                .setNegativeButton("Cancel", new DialogInterface.OnClickListener() {
                    public void onClick(DialogInterface dialog, int id) {
                        LookupWordDialogFragment.this.getDialog().cancel();
                    }
                });
        return builder.create();
    }
}

代码当前在此行上因空指针异常而崩溃：

activity.onFinishEditDialog(lookupWordEdit.getText().toString());

我怀疑我没有正确抓住lookupWordEdit。对话框非常简单。当用户点击 OK 按钮时，我应该如何获取输入的文本？

谢谢！

4

2 回答 2

2

你需要改变这个

 AlertDialog.Builder builder = new AlertDialog.Builder(getActivity());
 View view = getActivity().getLayoutInflater().inflate(R.layout.dialog_lookupword, null);
 builder.setView(view);

现在在这里你很少在里面使用 EditTextAlertDialog

EditText lookupWordEdit = (EditText)view.findViewById(R.id.lookupWordEdit);
于 2013-05-24T06:19:42.287 回答
0

lookupWordEditEditText 位于 AlertDialog 布局而不是DialogFragment布局内，因此您需要使用传入的相同 View 实例来setView从AlertDialogAlertDialog 布局访问 EditText 执行以下操作：

LayoutInflater inflater = LayoutInflater.from(getActivity());
View dialogview = inflater.inflate(R.layout.dialog_lookupword, null);
// now pass dialogview to setView of Dialog
builder.setView(dialogview);
.....

现在用于从布局dialogview初始化 EditText为：dialog_lookupword

EditText lookupWordEdit = (EditText)dialogview.findViewById(R.id.lookupWordEdit);
于 2013-05-24T06:22:32.533 回答