1

我正在做一个测验项目，该项目还允许用户添加新问题。

我有一个数组列表，其中存储和检索问题以进行显示。保存在数组列表中的每个对象包含 5 个字符串。

  • 问题
  • 正确答案
  • 错误答案 1
  • 错误答案 2
  • 错误答案 3

如何从数组列表中随机选择要显示在屏幕上的对象？以及如何随机播放 4 个答案（作为单选按钮），以便每次正确答案出现在不同的位置？

    namespace quiz
{
    public partial class Quiz : Form
    {
        private ArrayList Questionslist;

        public Quiz(ArrayList list)
        {
            InitializeComponent();
            Questionslist = list;
        }

        int index = 0;
        private void Quiz_Load(object sender, EventArgs e)
        {
            //creating an object of class Question and copying the object at index1 from arraylist into it  
            Question q = (Question)Questionslist[index];
            //to display the contents
            lblQs.Text = q.Quest;
            radioButtonA1.Text = q.RightAnswer;
            radioButtonA2.Text = q.WrongAnswer1;
            radioButtonA3.Text = q.WrongAnswer2;
            radioButtonA4.Text = q.WrongAnswer3;            
        }

        private int Score = 0;

        private void radioButtonA1_CheckedChanged(object sender, EventArgs e)
        {
            //if checkbox is checked
            //displaying text in separate two lines on messagebox
            if (radioButtonA1.Checked == true)
            {
                MessageBox.Show("Well Done" + Environment.NewLine + "You Are Right");
                Score++;
                index++;

                if (index < Questionslist.Count)
                {
                    radioButtonA1.Checked = false;
                    radioButtonA2.Checked = false;
                    radioButtonA3.Checked = false;
                    radioButtonA4.Checked = false;
                    Quiz_Load(sender, e);
                }
                else
                {
                    index--;
                    MessageBox.Show("Quiz Finished" + Environment.NewLine + "your Score is" + Score);
                    Close();
                }
            }
        }

        private void radioButtonA2_CheckedChanged(object sender, EventArgs e)
        {
            if (radioButtonA2.Checked == true)
            {
                MessageBox.Show("Sorry" + Environment.NewLine + "You Are Wrong");
                Close();
            }
        }

        private void radioButtonA3_CheckedChanged(object sender, EventArgs e)
        {
            if (radioButtonA3.Checked == true)
            {
                MessageBox.Show("Sorry" + Environment.NewLine + "You Are Wrong");
                Close();
            }
        }

        private void radioButtonA4_CheckedChanged(object sender, EventArgs e)
        {
            if (radioButtonA4.Checked == true)
            {
                MessageBox.Show("Sorry" + Environment.NewLine + "You Are Wrong");
                Close();
            }
        }
    }
}

这是课堂问题的代码

namespace quiz
{
    [Serializable()]
    public class Question : ISerializable
    {
        public String Quest;
        public String RightAnswer;
        public String WrongAnswer1;
        public String WrongAnswer2;
        public String WrongAnswer3;

        public Question()
        {
           Quest = null;
           RightAnswer=null;
           WrongAnswer1=null;
           WrongAnswer2=null;
           WrongAnswer3=null;
        }

        //serialization function
        public void GetObjectData(SerializationInfo info, StreamingContext context)
        {
            info.AddValue("Question", Quest);
            info.AddValue("Right Answer", RightAnswer);
            info.AddValue("WrongAnswer1",WrongAnswer1);
            info.AddValue("WrongAnswer2",WrongAnswer2);
            info.AddValue("WrongAnswer3",WrongAnswer3);
        }

        //deserializaton constructor
        public Question(SerializationInfo info, StreamingContext context)
        {
            Quest = (String)info.GetValue("Question", typeof(String));
            RightAnswer=(String)info.GetValue("Right Answer",typeof(String));
            WrongAnswer1=(String)info.GetValue("WrongAnswer1",typeof(String));
            WrongAnswer2=(String)info.GetValue("WrongAnswer2",typeof(String));
            WrongAnswer3=(String)info.GetValue("WrongAnswer3",typeof(String));
        }     
    }
}
4

7 回答 7

1

您知道哪一个是基于Text属性的“正确”答案。一种方法是将答案存储在一个数组中，并在将其分配给单选按钮之前对数组进行洗牌：

// You're going to make questionList a List<Question> because if you like
// Right answers you know that ArrayList is Wrong.
Question q = questionList[index];

// You should move this next bit to the Question class
string[] answers = new string[]
    {
        q.RightAnswer,
        q.WrongAnswer1,
        q.WrongAnswer2,
        q.WrongAnswer3
    };

// Using the Fisher-Yates shuffle from:
// http://stackoverflow.com/questions/273313/randomize-a-listt-in-c-sharp
Shuffle(answers);

// Ideally: question.GetShuffledAnswers()

radioButtonA1.Text = answers[0];
radioButtonA2.Text = answers[1];
radioButtonA3.Text = answers[2];
radioButtonA4.Text = answers[3];

然后，您只需要一个它们都共享的单选按钮事件处理程序：

private void radioButton_CheckedChanged(object sender, EventArgs e)
{
    RadioButton rb = (RadioButton)sender;
    Question q = questionList[index];

    //if checkbox is checked
    //displaying text in separate two lines on messagebox
    if (rb.Checked && q.RightAnswer == rb.Text)
    {
        // Move your code to another method
        // MessageBox.Show("Well Done" + Environment.NewLine + "You Are Right");
        UserSelectedCorrectAnswer();
    }
    else if (rb.Checked)
    {
        // They checked the radio button, but were wrong!
        // MessageBox.Show("Sorry" + Environment.NewLine + "You Are Wrong");
        UserSelectedWrongAnswer();
    }
}
于 2013-05-23T15:09:07.627 回答
1

从 ArrayList 中选择一个随机字符串：

string randomPick(ArrayList strings)
{
    return strings[random.Next(strings.Length)];
}

你可以考虑Question上课。这将包含string Text问题的成员（因为我认为 Question.Question 很愚蠢，Question.Text 在阅读时更有意义）。既然您提到了一个ArrayList（不是因为我认为这是最好的解决方案），您也可以将其中一个作为成员，其中包含所有潜在的答案。

创建问题时，您可以显示Question.Text，然后使用上面的功能随机选择一个答案。然后RemoveAt(index)在答案上使用以确保您不会重复答案。

于 2013-05-23T14:27:04.163 回答
1

我会创建一个Question包含问题、正确答案和可能答案列表的类，并具有以随机顺序返回可能答案并将猜测与正确答案进行比较的方法。它可能看起来像这样：

class Question
{
    String question;
    String rightAnswer;
    List<String> possibleAnswers = new ArrayList<String>();

    public Question(String question, String answer, List<String> possibleAnswers)
    {
      this.question = question;
      this.rightAnswer = answer;
      this.possibleAnswers.addAll(possibleAnswers);
      this.possibleAnswers.add(this.rightAnswer);
    }

    public List<String> getAnswers()
    {
        Collections.shuffle(possibleAnswers);
        return possibleAnswers;
    }

    public boolean isCorrect(String answer)
    {
      return answer.equals(correctAnswer);
    }
}
于 2013-05-23T14:31:01.627 回答
0

您应该将所有问题封装在一个类中。例如，创建一个名为Question. 此类可以包含 5 个变量：String question、String answer1、String answer2和。String answer3String answer4

将所有问题保存在数据库中或从文件中读取它们并在程序启动时加载它们。

使用Random类随机选择一个问题并“随机播放”这 4 个问题。

于 2013-05-23T14:25:35.917 回答
0

这是一个可行的方法：

public List<string> Randomize(string[] numbers)
{
    List<string> randomized = new List<string>();
    List<string> original = new List<string>(numbers);
    Random r = new Random();
    while (original.Count > 0) {
        int index = r.Next(original.Count);
        randomized.Add(original[index]);
        original.RemoveAt(index);
    }

return randomized;
}

只需将其调整为字符串数组而不是 int 数组

于 2013-05-23T14:28:23.833 回答
0

感谢所有回答我问题的人。我是这样做的。

 private void Quiz_Load(object sender, EventArgs e)
    {
        displayQs();
    }

    private void displayQs()
    {
            Random _random = new Random();
            int z = _random.Next(Questions.Count);
            Question q = (Question)Questions[z];
            Qslbl.Text = q.Quest;
            DisplayAns(q, _random);
    }

    private void DisplayAns(Question q, Random _random)
    {
        int j = 0;
        int[] array = new int[4];
        for (int i = 0; j <= 3; i++)
        {
            int x = _random.Next(4);
            x++;
            if (array.Contains(x))
            {
                continue;
            }
            else
            {
                array[j] = x;
                j++;
                string answer = null;
                if (j == 1)
                    answer = q.RightAnswer;
                else if (j == 2)
                    answer = q.WrongAnswer1;
                else if (j == 3)
                    answer = q.WrongAnswer2;
                else if (j == 4)
                    answer = q.WrongAnswer3;

                if (x == 1)
                    radioButton1.Text = answer;
                else if (x == 2)
                    radioButton2.Text = answer;
                else if (x == 3)
                    radioButton3.Text = answer;
                else if (x == 4)
                    radioButton4.Text = answer;
            }
        }
    }
于 2013-06-06T06:03:38.707 回答
0

洗牌可能是一个标准问题，但我想这会起作用：

// Warning: Not a thread-safe type.
// Will be corrupted if application is multi-threaded.
static readonly Random randomNumberGenerator = new Random();


// Returns a new sequence whose elements are
// the elements of 'inputListOrArray' in random order
public static IEnumerable<T> Shuffle<T>(IReadOnlyList<T> inputListOrArray)
{
  return GetPermutation(inputListOrArray.Count).Select(x => inputListOrArray[x]);
}
static IEnumerable<int> GetPermutation(int n)
{
  var list = Enumerable.Range(0, n).ToArray();
  for (int idx = 0; idx < n; ++idx)
  {
    int swapWith = randomNumberGenerator.Next(idx, n);
    yield return list[swapWith];
    list[swapWith] = list[idx];
  }
}

如果您没有IReadOnlyList<T>（.NET 4.5），只需使用IList<T>. 传入的对象没有发生变异。

于 2013-05-23T14:56:57.750 回答