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我正在尝试读取包含格式数据的 csv 文件：

02/01/2012  03/01/2012  04/01/2012  05/01/2012  06/01/2012 09/01/2012 10/01/2012
1w  0.652   0.626   0.606   0.584   0.564   0.546   0.53
2w  0.738   0.716   0.7 0.68    0.662   0.645   0.628
3w  0.845   0.826   0.808   0.785   0.762   0.746   0.734
1m  1.005   0.988   0.97    0.951   0.93    0.912   0.894
2m  1.165   1.152   1.137   1.122   1.105   1.092   1.083
3m  1.343   1.333   1.319   1.303   1.288   1.276   1.267
4m  1.425   1.416   1.403   1.387   1.372   1.362   1.355

我已阅读帖子： 当文件中的内容具有不同格式时，如何使用“csvread”？

在 MATLAB 中从 CSV 文件中读取日期和时间

但我仍然无法弄清楚如何读取包含表示日期的字符串的第一行并将其转换为 matlab 日期格式。

4

1 回答 1

4

尝试以下操作：

%# open file for reading
fid = fopen('file.csv', 'rt');

%# read first line and extract date strings
dt = textscan(fgetl(fid), '%s');

%# read the rest of the data
D = textscan(fid, '%s %f %f %f %f %f %f %f', 'CollectOutput',1);

%# close file
fclose(fid);

%# convert to serial date numbers
dt = datenum(dt{1}, 'mm/dd/yyyy')

%# place data in individual cells
D = [D{1} num2cell(D{2})]

结果：

dt =
      734900
      734929
      734960
      734990
      735021
      735113
      735143
D = 
    '1w'    [0.652]    [0.626]    [0.606]    [0.584]    [0.564]    [0.546]    [ 0.53]
    '2w'    [0.738]    [0.716]    [  0.7]    [ 0.68]    [0.662]    [0.645]    [0.628]
    '3w'    [0.845]    [0.826]    [0.808]    [0.785]    [0.762]    [0.746]    [0.734]
    '1m'    [1.005]    [0.988]    [ 0.97]    [0.951]    [ 0.93]    [0.912]    [0.894]
    '2m'    [1.165]    [1.152]    [1.137]    [1.122]    [1.105]    [1.092]    [1.083]
    '3m'    [1.343]    [1.333]    [1.319]    [1.303]    [1.288]    [1.276]    [1.267]
    '4m'    [1.425]    [1.416]    [1.403]    [1.387]    [1.372]    [1.362]    [1.355]
于 2013-05-23T13:48:32.580 回答