2

这是我的 XML。

<Operations>
<Operation Name="OperationName1">Entity details1</Operation>
<Operation Name="OperationName2">Entity details2</Operation>
<Operation Name="OperationName3">Entity details3</Operation>
<Operation Name="OperationName4">Entity details4</Operation>
</Operations>

在此我需要将每个子节点作为字符串变量读取。使用 DOM 我正在​​尝试这样。

NodeList items = root.getElementsByTagName("Operation");

        for (int i=0;i<items.getLength();i++)
        {   
            Node item = items.item(i);

            NodeList properties = item.getChildNodes();

            for (int j=0;j<properties.getLength();j++){

                Node property = properties.item(j);

                    }               
         }

现在据我所知,这些项目现在拥有所有子节点,我需要像这样存储每个子节点。

String ch_node="<Operation Name="OperationName4">Entity details4</Operation>"

是否有任何默认方法可以为我提供子节点 xml,或者我需要使用节点名称、值和属性再次创建?

我也尝试过使用 SAX 解析器,但不知道如何获取。

public void startElement(String uri, String localName, String qName,
        Attributes attributes) throws SAXException {       
    if (qName.equalsIgnoreCase("operation")) {     
        op_Name=attributes.getValue(0);
    }
}

public void characters(char[] ch, int start, int length)
        throws SAXException {        
}

public void endElement(String uri, String localName, String qName)
        throws SAXException {       
}
4

3 回答 3

1

你可以试试 DOM 和 Transformer

    Transformer tx = TransformerFactory.newInstance().newTransformer();
    tx.setOutputProperty(OutputKeys.OMIT_XML_DECLARATION, "yes");
    Document doc = DocumentBuilderFactory.newInstance().newDocumentBuilder().parse(new File("1.xml"));
    NodeList list = doc.getElementsByTagName("Operation");
    for (int i = 0; i < list.getLength(); i++) {
        DOMSource src = new DOMSource(list.item(i));
        StringWriter sr = new StringWriter();
        Result res = new StreamResult(sr);
        tx.transform(src, res);
        System.out.println(sr);
    }

输出

<Operation Name="OperationName1">Entity details1</Operation>
<Operation Name="OperationName2">Entity details2</Operation>
<Operation Name="OperationName3">Entity details3</Operation>
<Operation Name="OperationName4">Entity details4</Operation>
于 2013-05-23T05:47:08.273 回答
0

尝试这个

String elemName;

public void startElement(String uri, String localName, String qName,
        Attributes attributes) throws SAXException {       
   elemName=qName;
}

public void characters(char[] ch, int start, int length)
        throws SAXException {  
if(elemName.equals("OperationName1")) {
 String OperationName1Text=new String(ch);
}     
}

public void endElement(String uri, String localName, String qName)
        throws SAXException {       
}
于 2013-05-23T05:39:12.853 回答
0

请看下面的代码,这里我获取了一个子节点“描述”

URL url;

try {

    url = new URL(urls);
    HttpURLConnection conn = (HttpURLConnection) url.openConnection();
    if ((conn.getResponseCode() == HttpURLConnection.HTTP_OK)) {
        DocumentBuilderFactory dbf = DocumentBuilderFactory
                .newInstance();
        DocumentBuilder db = dbf.newDocumentBuilder();
        Document doc;
        doc = db.parse(url.openStream());
        doc.getDocumentElement().normalize();

        NodeList itemLst = doc.getElementsByTagName("item");
        nl = doc.getElementsByTagName(KEY_HEAD);

        Description = new String[itemLst.getLength()];// ........


        for (int i = 0; i < itemLst.getLength(); i++) {

            Node item = itemLst.item(i);
            if (item.getNodeType() == Node.ELEMENT_NODE) {
                Element ielem = (Element) item;

                NodeList description = ielem
                        .getElementsByTagName("description");

                Desc[i] = description.item(0).getChildNodes().item(0)
                        .getNodeValue();

            }

        }

    }
} catch (MalformedURLException e) {
    // TODO Auto-generated catch block
    e.printStackTrace();
} catch (DOMException e) {
    // TODO Auto-generated catch block
    e.printStackTrace();
} catch (IOException e) {
    // TODO Auto-generated catch block
    e.printStackTrace();
} catch (ParserConfigurationException e) {
    // TODO Auto-generated catch block
    e.printStackTrace();
} catch (SAXException e) {
    // TODO Auto-generated catch block
    e.printStackTrace();
}
于 2013-05-23T05:40:11.283 回答