python - Python3 错误：TypeError：无法将“字节”对象隐式转换为 str

Question

我正在 learnpythonthehardway 中的练习 41 并不断收到错误：

  Traceback (most recent call last):
  File ".\url.py", line 72, in <module>
    question, answer = convert(snippet, phrase)
  File ".\url.py", line 50, in convert
    result = result.replace("###", word, 1)
TypeError: Can't convert 'bytes' object to str implicitly

我使用的是python3，而书籍使用的是python2，所以我做了一些改变。这是脚本：

#!/usr/bin/python
# Filename: urllib.py

import random
from random import shuffle
from urllib.request import urlopen
import sys

WORD_URL = "http://learncodethehardway.org/words.txt"
WORDS = []

PHRASES = {
            "class ###(###):":
                "Make a class named ### that is-a ###.",
            "class ###(object):\n\tdef __init__(self, ***)" :
                "class ### has-a __init__ that takes self and *** parameters.",
            "class ###(object):\n\tdef ***(self, @@@)":
                "class ### has-a funciton named *** that takes self and @@@ parameters.",
            "*** = ###()":
                "Set *** to an instance of class ###.",
            "***.*** = '***'":
                "From *** get the *** attribute and set it to '***'."
}

# do they want to drill phrases first
PHRASE_FIRST = False
if len(sys.argv) == 2 and sys.argv[1] == "english":
    PHRASE_FIRST = True

# load up the words from the website
for word in urlopen(WORD_URL).readlines():
    WORDS.append(word.strip())

def convert(snippet, phrase):
    class_names = [w.capitalize() for w in
                    random.sample(WORDS, snippet.count("###"))]
    other_names = random.sample(WORDS, snippet.count("***"))
    results = []
    param_names = []

    for i in range(0, snippet.count("@@@")):
        param_count = random.randint(1,3)
        param_names.append(', '.join(random.sample(WORDS, param_count)))

    for sentence in snippet, phrase:
        result = sentence[:]

        # fake class names
        for word in class_names:
            result = result.replace("###", word, 1)

        # fake other names
        for word in other_names:
            result = result.replace("***", word, 1)

        # fake parameter lists
        for word in param_names:
            result = result.replace("@@@", word, 1)

        results.append(result)

    return results

# keep going until they hit CTRL-D
try:
    while True:
        snippets = list(PHRASES.keys())
        random.shuffle(snippets)

        for snippet in snippets:
            phrase = PHRASES[snippet]
            question, answer = convert(snippet, phrase)
            if PHRASE_FIRST:
                question, answer = answer, question

            print(question)

            input("> ")
            print("ANSWER: {}\n\n".format(answer))
except EOFError:
    print("\nBye")

我在这里到底做错了什么？谢谢！

Answer 1

urlopen()返回一个字节对象，要对其执行字符串操作，您应该str首先将其转换为。

for word in urlopen(WORD_URL).readlines():
    WORDS.append(word.strip().decode('utf-8')) # utf-8 works in your case

要获得正确的字符集： 如何在 python 中下载任何（！）具有正确字符集的网页？

Answer 2

在 Python 3 中，该urlopen函数返回一个HTTPResponse对象，其作用类似于二进制文件。所以，当你这样做时：

for word in urlopen(WORD_URL).readlines():
    WORDS.append(word.strip())

…你最终得到一堆bytes对象而不是str对象。所以当你这样做时：

result = result.replace("###", word, 1)

…你最终试图用一个对象替换字符串"###"中的字符串，而不是一个. 因此错误：resultbytesstr

TypeError: Can't convert 'bytes' object to str implicitly

答案是在获得单词后立即对其进行显式解码。为此，您必须从 HTTP 标头中找出正确的编码。你是怎样做的？

在这种情况下，我阅读了标题，我可以看出它是 ASCII，而且它显然是一个静态页面，所以：

for word in urlopen(WORD_URL).readlines():
    WORDS.append(word.strip().decode('ascii'))

但在现实生活中，您通常需要编写代码来读取标题并动态计算出来。或者，更好的是，安装一个更高级别的库requests，例如它会自动为您执行此操作。

Answer 3

将字节类型'word'显式转换为字符串

result = result.replace("###", sre(word), 1)

它应该工作