520

Requests是一个非常好的库。我想用它来下载大文件（> 1GB）。问题是不可能将整个文件保存在内存中。我需要分块阅读。这是以下代码的问题：

import requests

def DownloadFile(url)
    local_filename = url.split('/')[-1]
    r = requests.get(url)
    f = open(local_filename, 'wb')
    for chunk in r.iter_content(chunk_size=512 * 1024): 
        if chunk: # filter out keep-alive new chunks
            f.write(chunk)
    f.close()
    return

由于某种原因，它不能以这种方式工作：它仍然在将响应保存到文件之前将其加载到内存中。

更新

如果你需要一个可以从 FTP 下载大文件的小客户端（Python 2.x /3.x），你可以在这里找到它。它支持多线程和重新连接（它确实监视连接），它还为下载任务调整套接字参数。

4

7 回答 7

831

使用以下流式代码，无论下载文件的大小如何，Python 内存使用都会受到限制：

def download_file(url):
    local_filename = url.split('/')[-1]
    # NOTE the stream=True parameter below
    with requests.get(url, stream=True) as r:
        r.raise_for_status()
        with open(local_filename, 'wb') as f:
            for chunk in r.iter_content(chunk_size=8192): 
                # If you have chunk encoded response uncomment if
                # and set chunk_size parameter to None.
                #if chunk: 
                f.write(chunk)
    return local_filename

请注意，使用返回的字节数iter_content不完全是chunk_size; 预计它是一个通常更大的随机数，并且预计在每次迭代中都会有所不同。

请参阅body-content-workflow和Response.iter_content以获取更多参考。

于 2013-05-22T15:52:40.763 回答
423

如果您使用Response.rawand会容易得多shutil.copyfileobj()：

import requests
import shutil

def download_file(url):
    local_filename = url.split('/')[-1]
    with requests.get(url, stream=True) as r:
        with open(local_filename, 'wb') as f:
            shutil.copyfileobj(r.raw, f)

    return local_filename

这将文件流式传输到磁盘而不使用过多的内存，并且代码很简单。

注意：根据文档，Response.raw不会解码和传输编码，因此您需要手动执行此操作。gzipdeflate

于 2016-08-30T02:13:18.890 回答
82

不完全是 OP 的要求，但是......用以下方法做到这一点非常容易urllib：

from urllib.request import urlretrieve
url = 'http://mirror.pnl.gov/releases/16.04.2/ubuntu-16.04.2-desktop-amd64.iso'
dst = 'ubuntu-16.04.2-desktop-amd64.iso'
urlretrieve(url, dst)

或者这样，如果你想把它保存到一个临时文件中：

from urllib.request import urlopen
from shutil import copyfileobj
from tempfile import NamedTemporaryFile
url = 'http://mirror.pnl.gov/releases/16.04.2/ubuntu-16.04.2-desktop-amd64.iso'
with urlopen(url) as fsrc, NamedTemporaryFile(delete=False) as fdst:
    copyfileobj(fsrc, fdst)

我观察了这个过程：

watch 'ps -p 18647 -o pid,ppid,pmem,rsz,vsz,comm,args; ls -al *.iso'

我看到文件在增长，但内存使用量保持在 17 MB。我错过了什么吗？

于 2017-06-05T22:13:45.527 回答
43

您的块大小可能太大，您是否尝试过删除它 - 一次可能 1024 个字节？（另外，你可以with用来整理语法）

def DownloadFile(url):
    local_filename = url.split('/')[-1]
    r = requests.get(url)
    with open(local_filename, 'wb') as f:
        for chunk in r.iter_content(chunk_size=1024): 
            if chunk: # filter out keep-alive new chunks
                f.write(chunk)
    return

顺便说一句，您如何推断响应已加载到内存中？

听起来好像python没有将数据刷新到文件，从其他SO问题你可以尝试强制文件写入和释放内存f.flush()；os.fsync()

    with open(local_filename, 'wb') as f:
        for chunk in r.iter_content(chunk_size=1024): 
            if chunk: # filter out keep-alive new chunks
                f.write(chunk)
                f.flush()
                os.fsync(f.fileno())
于 2013-05-22T15:02:49.723 回答
8

改用wgetpython模块。这是一个片段

import wget
wget.download(url)
于 2020-10-19T04:09:45.450 回答
7

基于上面罗马人最赞成的评论，这是我的实现，包括“下载为”和“重试”机制：

def download(url: str, file_path='', attempts=2):
    """Downloads a URL content into a file (with large file support by streaming)

    :param url: URL to download
    :param file_path: Local file name to contain the data downloaded
    :param attempts: Number of attempts
    :return: New file path. Empty string if the download failed
    """
    if not file_path:
        file_path = os.path.realpath(os.path.basename(url))
    logger.info(f'Downloading {url} content to {file_path}')
    url_sections = urlparse(url)
    if not url_sections.scheme:
        logger.debug('The given url is missing a scheme. Adding http scheme')
        url = f'http://{url}'
        logger.debug(f'New url: {url}')
    for attempt in range(1, attempts+1):
        try:
            if attempt > 1:
                time.sleep(10)  # 10 seconds wait time between downloads
            with requests.get(url, stream=True) as response:
                response.raise_for_status()
                with open(file_path, 'wb') as out_file:
                    for chunk in response.iter_content(chunk_size=1024*1024):  # 1MB chunks
                        out_file.write(chunk)
                logger.info('Download finished successfully')
                return file_path
        except Exception as ex:
            logger.error(f'Attempt #{attempt} failed with error: {ex}')
    return ''
于 2020-07-05T17:15:42.380 回答
0

requests很好，但如何socket解决？

def stream_(host):
    import socket
    import ssl
    with socket.socket(socket.AF_INET, socket.SOCK_STREAM) as sock:
        context = ssl.create_default_context(Purpose.CLIENT_AUTH)
        with context.wrap_socket(sock, server_hostname=host) as wrapped_socket:
            wrapped_socket.connect((socket.gethostbyname(host), 443))
            wrapped_socket.send(
                "GET / HTTP/1.1\r\nHost:thiscatdoesnotexist.com\r\nAccept: text/html,application/xhtml+xml,application/xml;q=0.9,image/avif,image/webp,image/apng,*/*;q=0.8,application/signed-exchange;v=b3;q=0.9\r\n\r\n".encode())

            resp = b""
            while resp[-4:-1] != b"\r\n\r":
                resp += wrapped_socket.recv(1)
            else:
                resp = resp.decode()
                content_length = int("".join([tag.split(" ")[1] for tag in resp.split("\r\n") if "content-length" in tag.lower()]))
                image = b""
                while content_length > 0:
                    data = wrapped_socket.recv(2048)
                    if not data:
                        print("EOF")
                        break
                    image += data
                    content_length -= len(data)
                with open("image.jpeg", "wb") as file:
                    file.write(image)
于 2021-10-02T19:19:03.323 回答