1

只是想知道任何人都可以看到编写此查询的更简洁的方法。这对我来说似乎有很多重复，但我看不到更简单的方法来编写它。它正在撤回年初至今的数据。

输出如下所示：

name  Total New Drives  Total New Sales  Total Used Drives Total Used Sales    
Alan    41                31                 15               93    
Pascal  45                51                 35               33

查询是：

select sp.name, x.ttlNewTestDrives, x.ttlNewSales, y.ttlUsedTestDrives, y.TtlUsedSales
from
(
    select ts.SalesPersonID, ttd.TotalTestDrives as TtlNewTestDrives ,ts.TotalSales as TtlNewSales
    from
    (       
            select  sp.[SalesPersonID], count([TestDriveID]) as TotalTestDrives
            from SalesPeople sp
            join TestDrives td 
            on sp.[SalesPersonID] = td.[SalesPerson_SalesPersonID]
            join cars c on
            c.[CarID] = td.[Car_CarID]
            where c.CarType = 'New'
            group by sp.[SalesPersonID]
        ) as ttd
    full outer join
        (
            select sp.[SalesPersonID], count(SaleID) as TotalSales
            from Sales s
            join SalesPeople sp
            on s.[Salesperson_SalesPersonID] = sp.[SalesPersonID]
            join cars c on
            s.[Car_CarID] = c.[CarID]
            where c.CarType = 'New'
            group by sp.[SalesPersonID]
        ) as ts
    on ts.[SalesPersonID] = ttd.[SalesPersonID]
    ) as x
full outer join
(   
        select ttd.SalesPersonID, ttd.TotalTestDrives as TtlUsedTestDrives ,ts.TotalSales as TtlUsedSales
        from
        (       
                select  sp.[SalesPersonID], count([TestDriveID]) as TotalTestDrives
                from SalesPeople sp
                join TestDrives td 
                on sp.[SalesPersonID] = td.[SalesPerson_SalesPersonID]
                join cars c on
                c.[CarID] = td.[Car_CarID]
                where c.CarType = 'Used'
                group by sp.[SalesPersonID]
            ) as ttd
        full outer join
            (
                select sp.[SalesPersonID], count(SaleID) as TotalSales
                from Sales s
                join SalesPeople sp
                on s.[Salesperson_SalesPersonID] = sp.[SalesPersonID]
                join cars c on
                s.[Car_CarID] = c.[CarID]
                where c.CarType = 'Used'
                group by sp.[SalesPersonID]
            ) as ts
        on ts.[SalesPersonID] = ttd.[SalesPersonID]
    ) y
on x.[SalesPersonID] = y.[SalesPersonID]
join SalesPeople sp
on x.[SalesPersonID] = sp.[SalesPersonID]
4

1 回答 1

3

您当然可以使用以下方法减少查询中的代码量：

select sp.name, td.NewTestDrives, s.NewSales, td.UsedTestDrives, s.NewSales
from SalesPeople sp
  left join
  (
    select td.[SalesPerson_SalesPersonID]
      , NewTestDrives = sum(case when c.CarType = 'New' then 1 else 0 end)
      , UsedTestDrives = sum(case when c.CarType = 'Used' then 1 else 0 end)
    from TestDrives td 
      inner join cars c on c.[CarID] = td.[Car_CarID]
  ) td on sp.SalesPersonID = td.[SalesPerson_SalesPersonID]
  left join
  (
    select s.[SalesPerson_SalesPersonID]
      , NewSales = sum(case when c.CarType = 'New' then 1 else 0 end)
      , UsedSales = sum(case when c.CarType = 'Used' then 1 else 0 end)
    from Sales s 
      inner join cars c on c.[CarID] = s.[Car_CarID]
  ) s on sp.SalesPersonID = s.[SalesPerson_SalesPersonID]

我已经消除了很多重复的联接，并从完全联接转移到将两个汇总结果集（试驾和销售）加入到销售人员表中。

您没有提供表或任何示例数据的详细信息，因此无法测试上述查询，但希望它能给您一些关于如何更简洁地编写它的想法。

就实际性能而言，我想简化代码可能会对优化器有所帮助，但这是您需要在自己的环境中确认的事情。

于 2013-05-22T10:40:07.310 回答