0

我想获得 10 个最近的经度和纬度位置。我将经度和纬度存储为双倍。我试过这个：

SELECT * FROM company as dest where 3956 * 2 * ASIN(SQRT( POWER(SIN((122.4058 - abs( dest.latitude)) * pi()/180 / 2),2) + COS(122.4058 * pi()/180 ) * COS( abs (dest.latitude) * pi()/180) * POWER(SIN((37.7907 – dest.longitude) * pi()/180 / 2), 2) )) as dis <10 and ORDER BY dis limit 10;

但我收到此错误：

#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '– dest.longitude) * pi()/180 / 2), 2) )) as dis <10 and ORDER BY dis limit 10 ' at line 1

如何解决这个错误？

4

2 回答 2

1

try this :

     POWER(SIN((37.7907 – abs(dest.longitude))

EDIT2:

     SELECT *,3956 * 2 * ASIN(SQRT( POWER(SIN((122.4058 - abs(dest.latitude)) * pi()/180 / 2),2) + COS(122.4058 * pi()/180 ) * COS( abs(dest.latitude) * pi()/180) * POWER(SIN((37.7907 - abs(dest.longitude)) * pi()/180 / 2), 2) )) as dis FROM company as dest HAVING dis <10 ORDER BY dis limit 10;
于 2013-05-22T10:10:13.960 回答
1

我复制了您的 sql 代码并将其放入具有语法高亮支持 (Sublime2) 的编辑器中，错误指向的字符（看起来像减号）实际上是另一个符号..

根据此网页，此字符称为 EN DASH（您可以在链接末尾的 utf8-hex-code 中看到它:)） http://www.utf8-character.info/#!%E2%80%93

尝试用一个简单的减号替换这个字符。

于 2013-05-22T09:49:26.503 回答