如何在 Android 上只允许一键触摸?我不想支持多点触控,如果我的一根手指已经在触摸屏幕,我希望我的应用放弃其他触控。这就像在 iOS 上使用独家触控一样。
另外,有没有办法设置允许的触摸次数?
谢谢!
编辑:最小目标 API = 8。
如何在 Android 上只允许一键触摸?我不想支持多点触控,如果我的一根手指已经在触摸屏幕,我希望我的应用放弃其他触控。这就像在 iOS 上使用独家触控一样。
另外,有没有办法设置允许的触摸次数?
谢谢!
编辑:最小目标 API = 8。
是的,您可以使用此禁用多点触控android:splitMotionEvents="false"
或android:windowEnableSplitTouch="false"
您必须跟踪第一次触摸的指针 id 并仅使用与该触摸相对应的触摸事件。这是来自 官方 Android 博客“Make Sense of Multitouch”的一个很好的例子
private static final int INVALID_POINTER_ID = -1;
// The ‘active pointer’ is the one currently moving our object.
private int mActivePointerId = INVALID_POINTER_ID;
// Existing code ...
@Override
public boolean onTouchEvent(MotionEvent ev) {
final int action = ev.getAction();
switch (action & MotionEvent.ACTION_MASK) {
case MotionEvent.ACTION_DOWN: {
final float x = ev.getX();
final float y = ev.getY();
mLastTouchX = x;
mLastTouchY = y;
// Save the ID of this pointer
mActivePointerId = ev.getPointerId(0);
break;
}
case MotionEvent.ACTION_MOVE: {
// Find the index of the active pointer and fetch its position
final int pointerIndex = ev.findPointerIndex(mActivePointerId);
final float x = ev.getX(pointerIndex);
final float y = ev.getY(pointerIndex);
final float dx = x - mLastTouchX;
final float dy = y - mLastTouchY;
mPosX += dx;
mPosY += dy;
mLastTouchX = x;
mLastTouchY = y;
invalidate();
break;
}
case MotionEvent.ACTION_UP: {
mActivePointerId = INVALID_POINTER_ID;
break;
}
case MotionEvent.ACTION_CANCEL: {
mActivePointerId = INVALID_POINTER_ID;
break;
}
case MotionEvent.ACTION_POINTER_UP: {
// Extract the index of the pointer that left the touch sensor
final int pointerIndex = (action & MotionEvent.ACTION_POINTER_INDEX_MASK)
>> MotionEvent.ACTION_POINTER_INDEX_SHIFT;
final int pointerId = ev.getPointerId(pointerIndex);
if (pointerId == mActivePointerId) {
// This was our active pointer going up. Choose a new
// active pointer and adjust accordingly.
final int newPointerIndex = pointerIndex == 0 ? 1 : 0;
mLastTouchX = ev.getX(newPointerIndex);
mLastTouchY = ev.getY(newPointerIndex);
mActivePointerId = ev.getPointerId(newPointerIndex);
}
break;
}
}
return true;
}