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我希望有人可以帮助我，因为当我编辑我的代码时。异常显示

这是我的控制器

public IEnumerable<APPLICANT> GetApplicant()
{
    IEnumerable<APPLICANT> applicantdata = Cache.Get("applicants") as IEnumerable<APPLICANT>;

    if (applicantdata == null)
    {
        var data = from app in context.APPLICANTs
                   join a in context.Profiles
                   on app.Profile_id equals a.PROFILE_ID into output
                   from j in output.DefaultIfEmpty()
                   select new { 
                       Id = app.APPLICANT_ID, 
                       LastName = 
                           (j == null ? app.APPLICANT_LastName : j.Applicant_LASTNAME) 
                   };

        var applicant = data
            .Where(v => !String.IsNullOrEmpty(v.LastName))
            .Take(1000);

        applicantdata = (from a in applicant
                         select new APPLICANT() { 
                             APPLICANT_ID = a.Id, 
                             APPLICANT_LastName = a.LastName
                         }).AsEnumerable();

        if (applicantdata.Any())
        {
            Cache.Set("applicants", applicantdata, 30);
        }
    }

    return applicantdata;    
}

这是一个例外：

NotSupportedException 未被用户代码处理。实体或复杂类型“ ”未在 LINQ to Entities 查询中构造。LINQ ASP.NET

在这一行：

if (applicantdata.Any())
4

1 回答 1

0

在 Linq-to-Entities 中，您只能投影到任何现有的映射实体类型，但您可以投影到匿名类型

applicantdata = (from a in applicant
                     select new APPLICANT() { 
                         APPLICANT_ID = a.Id, 
                         APPLICANT_LastName = a.LastName
                     }).AsEnumerable();

在上面的代码中，您尝试投影为“APPLICANT”类型，因此它不允许您这样做。您可以尝试使用匿名类型来执行此操作：

applicantdata = (from a in applicant
                     select new { 
                         APPLICANT_ID = a.Id, 
                         APPLICANT_LastName = a.LastName
                     }).AsEnumerable();

希望这会有所帮助！

于 2013-05-22T06:31:53.257 回答