0

我想创建一个执行基本 CRUD 操作的存储库。

因为我有不同类型的照片（CompanyPhoto、CarPhoto、..），所以我更愿意让 JPA 存储库通用，但也让 EJB 服务也通用。

这是我的课程：

    @Entity
    @Inheritance
    @DiscriminatorColumn(name = "DESCRIMINATOR")
    @Table(name = "PHOTOS")
    public abstract class Photo {
        public Photo() {
        }

        public Photo(String fileName) {
            this.fileName = fileName;
    //      this.file = file;
        }

        @Id
        @GeneratedValue(strategy = GenerationType.TABLE, generator = "PHOTOS_SEQ")
        @TableGenerator(name = "PHOTOS_SEQ", table = "SEQUENCE", pkColumnName = "SEQ_NAME", pkColumnValue = "PHOTOS_SEQ", valueColumnName = "SEQ_COUNT", allocationSize = 50)
        @Column(nullable = false)
        private long id;

        @Column(length = 255)
        @Size(min = 0, max = 255, message = "{Photo.description.size}")
        protected String description;

        @Column(nullable = false, length = 255)
        @NotNull(message = "{Photo.fileName.notNull}")
        @Size(min = 1, max = 255, message = "{Photo.fileName.size}")
        protected String fileName;

        // ...

@Entity
@DiscriminatorValue("C")
public class CarPhoto extends Photo {

    public CarPhoto() {

    }

    public CarPhoto(String fileName) {
        super.fileName = fileName;
    }

    @ManyToOne(cascade = { CascadeType.DETACH })
    @JoinColumn(name = "CARID", nullable = false)
    @NotNull
    private Car car;
        // ...

@Entity
@DiscriminatorValue("P")
public class PersonPhoto extends Photo {

    public PersonPhoto() {

    }

    public PersonPhoto(String fileName) {
        super.fileName = fileName;
    }

    @ManyToOne(cascade = { CascadeType.DETACH })
    @JoinColumn(name = "PERSONID", nullable = false)
    @NotNull
    private Person person;
        // ...

@Stateless
@LocalBean
public class PhotoRepository<E> {

        // In this class I would like to do create, remove, update and some basic find       //operations..


    @PersistenceContext
    private EntityManager em;

    public PhotoRepository() {
    }

    PhotoRepository(EntityManager em) {
        this.em = em;
    }

    @Override
    public E create(E photo) {
        em.persist(photo);
        return photo;
    }

    @Override
    public E modify(E photo)
    {
        Class<E> photoClass;
                // QUESTION: How am I going to call the getId() method from the object of type E  class?
        em.find(photoClass, photo.getId()); // This will not work.. =(
        E mergedPhoto = em.merge(photo);
        return mergedPhoto;
    }
        // ...

我希望你明白我想表演什么。不同类型的类的通用存储库，这些类都继承自同一个基类。你能给我一些最佳实践的例子吗？=)

此致

4

2 回答 2

1

您可以使用从实体获取 Id，

entityManagerFactory.getPersistenceUnitUtil().getIdentifier(object);

虽然您不需要在 merge() 之前调用 find()，只需调用 merge()，它会在需要时进行查找。

于 2013-05-22T13:54:36.680 回答
1

更改泛型定义以说明 E 必须是从 Photo 扩展的任何类型。然后您将能够访问 Photo 类对 E 类型变量的方法

@Stateless
@LocalBean
public class PhotoRepository<E extends Photo> {

您可以使用以下方法来检索实际的类。

public Class getEntityClass() {
  ParameterizedType parameterizedType =
    (ParameterizedType) getClass().getGenericSuperClass();
 return (Class) parameterizedtype.getActualTypeArguments()[0];
}

如果您使用的是 spring，您还应该查看 spring-data-jpa - 它提供了这样的通用存储库实现。

于 2013-05-22T14:28:56.453 回答