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我正在尝试获取一个表单来将数据输入到我的“mysql 数据库”中，但是我收到一条错误消息，并且每次加载页面时它都会输入一个空白数据。

这是我的代码：

    <form action="insert.php" method="post">
Name: <input type="text" name="name">
<input type="submit" value="Submit">
</form>

<?php
// This is the connection to my database
$con = mysql_connect('127.0.0.1', 'shane', 'diamond89');
if (!$con){
die('Could not Connect: ' . mysql_error());
}

// This creates my table layout
echo "<table border='1'>
<tr>
<th>ID</th>
<th>Name</th>
<th>Delete</th>
</tr>";

// This selects which database i want to connect to
$selected = mysql_select_db("shane",$con);
if (!$con){
die("Could not select examples");
}

// This inserts new information to the Database
$query = "INSERT INTO test1 VALUES('id', '$name')";

$result = mysql_query($query);
if ($result){
echo("Input data is Successful");
}else{
echo("Input data failed");
}

// This chooses which results i want to select from
$result = mysql_query("SELECT `id`, `name` FROM `test1` WHERE 1");


// This outputs the information into my table
while ($row = mysql_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['id'] . "</td>";
echo "<td>" . $row['name'] . "</td>";
echo "<td>" . "[D]" . "</td>";
echo "</tr>";
}
echo "</table>";

// This closes my connection
mysql_close($con);

?>

这是错误消息：

( ! ) SCREAM: ( ! ) 忽略错误抑制 注意：未定义的变量：C:\wamp\www\sql_table.php 中第 36 行调用堆栈中的名称

时间记忆功能位置

1 0.0006 250360 {main}( ) ..\sql_table.php:0

4

1 回答 1

1

您正在尝试访问 POST 数据，因此您应该执行以下操作：

编辑：小心你放入数据库的数据。您应该使用现代数据库 API，或者至少转义您的数据（参见下面的代码）

<form action="insert.php" method="post">
Name: <input type="text" name="name">
<input type="submit" value="Submit">
</form>

<?php
// Following code will be called if you submit your form
if (!empty($_POST['name'])) :

// This is the connection to my database
$con = mysql_connect('127.0.0.1', 'shane', 'diamond89');
if (!$con){
die('Could not Connect: ' . mysql_error());
}

// This creates my table layout
echo "<table border='1'>
<tr>
<th>ID</th>
<th>Name</th>
<th>Delete</th>
</tr>";

// This selects which database i want to connect to
$selected = mysql_select_db("shane",$con);
if (!$con){
die("Could not select examples");
}

// This inserts new information to the Database
$query = "INSERT INTO test1 VALUES('id', \'".mysql_real_escape_string($_POST['name'])."\')";

$result = mysql_query($query);
if ($result){
echo("Input data is Successful");
}else{
echo("Input data failed");
}

// This chooses which results i want to select from
$result = mysql_query("SELECT `id`, `name` FROM `test1` WHERE 1");


// This outputs the information into my table
while ($row = mysql_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['id'] . "</td>";
echo "<td>" . $row['name'] . "</td>";
echo "<td>" . "[D]" . "</td>";
echo "</tr>";
}
echo "</table>";

// This closes my connection
mysql_close($con);

endif;
?>
于 2013-05-21T13:37:40.220 回答