2

问题改写:

HOMEDIR="ftpuser"
REMOTEIP="1.1.1.1"
MYSQLPASS="password"

Q1="DROP USER "$HOMEDIR"_shop;"
Q2="DROP DATABASE "$HOMEDIR"_shop;"
Q3="CREATE DATABASE IF NOT EXISTS "$HOMEDIR"_shop;"
Q4="GRANT ALL ON "$HOMEDIR"_shop TO '"$HOMEDIR"_shop'@'localhost' IDENTIFIED BY '$MYSQLPASS';"
Q5="GRANT ALL ON "$HOMEDIR"_shop TO '"$HOMEDIR"_shop'@'anotherip' IDENTIFIED BY '$MYSQLPASS';"
# Need to grant permissions from another server as well
Q6="FLUSH PRIVILEGES;"
SQL="${Q1}${Q2}${Q3}${Q4}${Q5}${Q6}"

echo $SQL
echo " "
ssh -p 8899 root@$REMOTEIP "mysql -u root -p "$SQL""

然后我运行:

/root/testing/migratesite.sh

并得到:

bash: DROP: command not found
bash: CREATE: command not found
bash: GRANT: command not found
bash: GRANT: command not found
bash: FLUSH: command not found

我错过了什么?

4

2 回答 2

3

您缺少引号和正确的 mysql 客户端命令行:

ssh -p 8899 root@$REMOTEIP "mysql -u root -p -e \"$SQL\""

您需要对 $SQL 变量周围的引号进行转义,以便将它们传递给远程 shell,否则它们会被本地 shell 解释(这就是你得到 DROP: command not found,分号由 shell 解释的原因。)此外,要让 mysql 客户端执行命令,您必须传递 -e 命令行选项。

于 2009-11-03T12:20:07.383 回答
0

你试过这个:

ssh -p 8899 root@$REMOTEIP "echo \"$SQL\" | mysql -u root --password=$SQL_PASS"
于 2009-11-03T12:20:31.933 回答