android - org.json.JSONException：值 我有一个方法，我使用 android 中的 http post 从 web 服务获取数据。 我的代码是， public class PropertyRequestService { static String result;

Question

我有一个方法，我使用 android 中的 http post 从 web 服务获取数据。

我的代码是，

public class PropertyRequestService  {

static String result;
PropertiesList localProperty = new PropertiesList();
List<PropertiesList> Properties;
List<PropertiesList> PropertiesRS;

public List<PropertiesList>  getAllPropertiesStuff() {

    try {

        HttpClient client = new DefaultHttpClient();
        HttpPost httppost = new HttpPost(
                "Here Given Webservice URL");
        List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
        nameValuePairs
                .add(new BasicNameValuePair("string", "value"));

        httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
        HttpResponse response = client.execute(httppost);

        HttpEntity entity = response.getEntity();
        if (entity != null) {


            InputStream instream = entity.getContent();
           String response1= convertStreamToString(instream);

            // Closing the input stream will trigger connection release
            instream.close();
            //result = EntityUtils.toString(entity);
            Log.i("RESPONSE=", response1);

            JSONObject json = new JSONObject(response1);

            PropertiesRS.add(SplitResult(json));
        }
    } catch (Exception e1) {
        e1.printStackTrace();
    }

    return PropertiesRS;
}

 public static String convertStreamToString(InputStream instream) {

     BufferedReader reader = new BufferedReader(new InputStreamReader(instream));
        StringBuilder sb = new StringBuilder();

        String line = null;
        try {
            while ((line = reader.readLine()) != null) {
                sb.append(line + "\n");
            }
        } catch (IOException e) {
            e.printStackTrace();
        } finally {
            try {
                instream.close();
            } catch (IOException e) {
                e.printStackTrace();
            }
        }
        return sb.toString();
}

这是日志猫，

05-21 11:44:27.320: W/System.err(13234): org.json.JSONException: Value <?xml of type java.lang.String cannot be converted to JSONObject
05-21 11:44:27.320: W/System.err(13234):    at org.json.JSON.typeMismatch(JSON.java:107)
05-21 11:44:27.320: W/System.err(13234):    at org.json.JSONObject.<init>(JSONObject.java:158)
05-21 11:44:27.328: W/System.err(13234):    at org.json.JSONObject.<init>(JSONObject.java:171)
05-21 11:44:27.328: W/System.err(13234):    at com.BuildersUpdate.PropertySearchTypes.PropertyRequestService.getAllPropertiesStuff(PropertyRequestService.java:68)

我的网络服务以这种格式返回数据，

05-21 11:44:27.320: I/RESPONSE=(13234): <?xml version="1.0" encoding="utf-8"?>
05-21 11:44:27.320: I/RESPONSE=(13234): <string xmlns="http://localhost/">[{"TbbId":0,"PropertyID":1066666,"BuilderID":"9250c666-e76c-4206-8b37-343b2bb11a89","BuilderName":"David Weekley Homes","Notes":"","Address":"1 TBB4307","SchoolDistrict":null,"School":null,"CityID":"Austin","CountyID":"","StateID":"TX","Zip":"78737","Lat":"30.192781000000000","Lng":"-97.984480000000000","Price":391990,"PropertyStatusID":"AV","PropertyStatusDescription":"Available","StageID":"TBB","StageDescription":"To-Be-Built Home","TypeID":1,"TypeDescription":"House","SubdivisionID":3312,"SubdivisionName":"Belterra","FloorPlanNumber":"4307","Remarks":"","OldNew":null,"PropertyInMyListFlag":null,"FreePostingFlag":"F","PropertySubscriptionPlan":null,"PropertySubscriptionPaymentType":null,"BalanceAmount":0,"PropertyLicenseFlag":"N","PlanNumber":null,"SubdivisionFloorPlanID":null,"SubdivisionFloorPlanName":"Newtown","ShowDirections":"Monday-Saturday 10am-6pm\nSunday 12pm-6pm ","DrivingDirections":"From HWY 290, Take 290 West towards Dripping Springs. Belterra is 7 miles past the intersection of 290 and 71 on the left. Turn left onto Belterra Drive. Turn right onto Abbott Drive, our model is on the left.","PropertyClass":"TBB","RemarksId":0,"VerifiedBU":"Y","SubdivisionDescription":null,"Contact1Name":"Rachea McMurray-Pendley","Contact1Phone":"866-933-5539","Contact1PhoneAlt":"","Contact2Name":"Telenna Thompson","Contact2Phone":"512-821-8821","Contact2PhoneAlt":"","Email":"","Beds":4,"Baths":3,"HalfBaths":1,"Living":0,"Dining":0,"OtherRooms":"","Stories":2.0,"Master":"Down","Garage":3.0,"SquareFeet":3320,"LotSize":"","LotDescription":"Enjoy a host of amenities and award-winning homes in Belterra, a premier community in Austin, Texas. Located just minutes from downtown Austin, Belterra offers residents the opportunity to live, work and play in a community that fits their lifestyle. Here, you can enjoy the &amp;ldquo;Exemplary&amp;rdquo; schools of Dripping Springs ISD plus: &amp;nbsp; Resort-style pool with splash pad for the kids Rooster Springs Elementary School on site Recreation center, outdoor pavilion, club house and fitness center Sport court, ball fields and several children's playscapes Over 400 acres dedicated to parks, sports fields and undisturbed green spaces Miles of walking trails to enjoy the great outdoors 70 x 130 homesites that back up to greenbelts with gorgeous hill country views Over 400 acres dedicated to parks, sports fields and undisturbed green space","CommunityTypeID":11,"CommunityTypeDescription":"Standard","LotWidth":0,"LotLength":0,"Acres":0,"Water":"","Sewer":"","DryUtilities":"","Topography":"","Trees":"","VirtualTourURL":"","InternetOption":"","WaterId":0,"SewerId":0,"DryUtilitiesId":0,"TopographyId":0,"TreesId":0,"InternetOptionId":0,"WaterIds":null,"SewerIds":null,"DryUtilitiesIds":null,"TopographyIds":null,"TreesIds":null,"InternetOptionIds":null,"MinimumPrice":0,"MaximumPrice":0,"MinimumPropertySquareFeet":0,"MaximumPropertySquareFeet":0,"MinimumBeds":0,"MaximumBeds":0,"MinimumBaths":0,"MaximumBaths":0,"MinimumHalfBaths":0,"MaximumHalfBaths":0,"MinimumStories":0,"MaximumStories":0,"MinimumGarages":0,"MaximumGarages":0,"IsModel":null,"CustomHomeModelId":0,"BrandName":null,"SchoolDistrictID":0,"SchoolDistrictName":null,"ElementarySchool":null,"MiddleSchool":null,"HighSchool":null,"SchoolComments":"Please visit the school district's website for additional information about attendance boundaries and school activities.","HasHOA":true,"HOA":"","HOAFee":106.25,"HOABillingPeriod":"Quarterly","CommissionPaid":"TBD","BuyerIncentive":"Please call for current incentives.","AgentIncentive":"Please call for current incentives.","PropertyImageID":5775047,"PropertyImage":"PropertyImages/20130316\\P1066666__031613163405_2040133366_5775047.jpg","IsModified":false,"StatusID":40,"StatusDescription":"Active","EntryDate":new Date(1350438245980),"ModifyDate":new Date(1363450564963),"AvailableDate":new Date(-59011459200000),"UserIDModifiedBy":"4a2aef16-e7d9-469a-95ad-5c8935cb6bab","UserIDApprovedBy":"0000000

我不知道为什么会引发此异常。

由于客户端要求的限制，我无法将应用程序更改为以 json 格式发送数据。

如何将响应转换为android中的json对象？这正在消耗我宝贵的时间，而不是继续前进。我被困在这里。

请有任何想法或建议！

提前致谢..

Answer 1

当您获得由 XML 标记覆盖的 JSON 响应时，您必须编写一个逻辑来为您提供该 JSON 数据。

/**
 * To fetch JSON Text between XML tags
 * For example: 
 * <string xmlns="http://schemas.microsoft.com/2003/10/Serialization/"> JSON Response text </string>
 * @param response
 * @return
 */
public String getJSONString(HttpResponse response) {

    try {
         DocumentBuilder builder = DocumentBuilderFactory.newInstance().newDocumentBuilder();
         Document doc = builder.parse(response.getEntity().getContent());
         NodeList nl = doc.getElementsByTagName("string");
         Node n = nl.item(0);
         String str = n.getFirstChild().getNodeValue();
         System.out.println("Node value : " + str);
         return str;
    } catch (ParserConfigurationException e) {
         e.printStackTrace();
    } catch (SAXException e) {
         e.printStackTrace();
    } catch (IllegalStateException e) {
         // TODO Auto-generated catch block
         e.printStackTrace();
    } catch (IOException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
 return null;
}