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我试图汇总标题名称和来自不同标题来源的数量。我成功地从对象数组中删除了重复项，并且仅从每个源中仅显示原始版本的标题，而没有任何重复项。但是我没有详细说明每个标题名称在 json 中有多少个重复项。就像在这里，我们每个人都有 4 个。但我无法获得全部重复项。这部分是我在代码中添加的else条件。ifExistFlag我还添加了一个小提琴链接

http://jsfiddle.net/wF4qX/5/

  var inputJson = [{
      "Sources": [{
          "title": "Title Name",
          "source": "SourceName1",
          "date": "07-05-2013 00:38:40",
          "link": "Link to 1"
        }, {
          "title": "Title Name",
          "date": "07-05-2013 00:24:17",
          "source": "SourceName2",
          "link": "Link to 2"
        }
      ]
    }, {
      "Sources": [{
          "title": "Title Name",
          "source": "SourceName1",
          "date": "07-05-2013 00:38:40",
          "link": "Link to 1"
        }, {
          "title": "Title Name",
          "date": "07-05-2013 00:24:17",
          "source": "SourceName2",
          "link": "Link to 2"
        }
      ]
    }, {
      "Sources": [{
          "title": "Title Name",
          "source": "SourceName1",
          "date": "07-05-2013 00:38:40",
          "link": "Link to 1"
        }, {
          "title": "Title Name",
          "date": "07-05-2013 00:24:17",
          "source": "SourceName2",
          "link": "Link to 2"
        }
      ]
    }, {
      "Sources": [{
          "title": "Title Name",
          "source": "SourceName1",
          "date": "07-05-2013 00:38:40",
          "link": "Link to 1"
        }, {
          "title": "Title Name",
          "date": "07-05-2013 00:24:17",
          "source": "SourceName2",
          "link": "Link to 2"
        }
      ]
    }
  ]
   $(document).ready(function () {
    var sourceList = AggregateSource(inputJson);
    var sourcePrint = printFinalSourceData(sourceList);
    $("#output").html(sourcePrint);
  });



  function AggregateSource(sourceArray, number) {
    var l = {};
    var finalArray = [];
    for (var i = 0; i < sourceArray.length; i++) {
      for (var j = 0; j < sourceArray[i].Sources.length; j++) {
        if (l.hasOwnProperty(sourceArray[i].Sources[j].source) == false) {
          l[sourceArray[i].Sources[j].source] = [];
          var m = {};
          m["title"] = sourceArray[i].Sources[j].title;
          m["link"] = sourceArray[i].Sources[j].link;
          m["date"] = sourceArray[i].Sources[j].timeStamp;
          m["count"] = 1;
          l[sourceArray[i].Sources[j].source].push(m);
        } else {
          var ifExistFlag = true;
          for (var k = 0; k < l[sourceArray[i].Sources[j].source].length; k++) {
            if (l[sourceArray[i].Sources[j].source][k]["title"] == sourceArray[i].Sources[j].title) {
              ifExistFlag = false;
            }
          }
          if (ifExistFlag == true) {
            m["title"] = sourceArray[i].Sources[j].title;
            m["date"] = sourceArray[i].Sources[j].timeStamp;
            m["link"] = sourceArray[i].Sources[j].link;
            l[sourceArray[i].Sources[j].source].push(m);
          } else {
            //  alert(l[sourceArray[i].Sources[j].source][j]["count"])
          }
        }
      }
    }
    finalArray.push(l);
    return finalArray;
  }



  function printFinalSourceData(inputArray) {
    var sourceHTML = '';
    for (var k = 0; k < inputArray.length; k++) {
      for (key in inputArray[k]) {
        for (var i = 0; i < inputArray[k][key].length; i++) {
          sourceHTML += "<span style='width:80%; float:left; font-size:14px;'><a href='" + inputArray[k][key][i].link + "' target='_blank' style='text-decoration:none; color:#333333; font-weight:bold;'>" + inputArray[k][key][i].title + "</a></span><br><span style='width:80%;float:left; font-size:10px; color: #3f4041;'>" + key.split("_").join(" "); + "</span><br>";
        }
      }
    }
    return sourceHTML;
  }
4

1 回答 1

1

那不是 JSON，那是一个 Javascript 数组。JSON 是一种表示数据的文本格式。

您的变量ifExistFlag将始终为假。如果您进入else，您已经知道已经存在一个具有相同来源的项目，即使它不存在，当j和k相等时，您也会将该项目与自身进行比较。正如您当时已经知道已经存在具有相同来源的项目，根本不需要检查。

不是将对象推入数组，而是将对象放入对象中l，当您找到另一个具有相同来源的对象时，您只需增加计数器。最后，只需返回对象，l而不是将其全部推送到数组中：

function AggregateSource(sourceArray, number) {
  var l = {};
  for (var i = 0; i < sourceArray.length; i++) {
    var s = sourceArray[i].Sources;
    for (var j = 0; j < s.length; j++) {
      if (!l.hasOwnProperty(s[j].source)) {
        l[s[j].source] = {
          title: s[j].title,
          link: s[j].link:
          date: s[j].timeStamp,
          count: 1
        };
      } else {
        l[s[j].source].count++;
      }
    }
  }
  return l;
}

由于您有一个包含对象的对象，而不是一个包含具有对象数组的对象的数组，因此printFinalSourceData函数中需要的循环要少得多：

function printFinalSourceData(inputArray) {
  var sourceHTML = '';
  for (key in inputArray) {
    sourceHTML +=
      "<span style='width:80%; float:left; font-size:14px;'>" +
      "<a href='" + inputArray[key].link + "' target='_blank' style='text-decoration:none; color:#333333; font-weight:bold;'>" +
      inputArray[key].title +
      "</a></span><br>" +
      "<span style='width:80%;float:left; font-size:10px; color: #3f4041;'>" +
      key.split("_").join(" "); +
      "</span><br>";
  }
  return sourceHTML;
}

inputArray[key].count如果要显示为每个来源找到的项目数，可以使用。

于 2013-05-21T05:58:09.010 回答