我目前正在研究未排序的链表检查,下面是我的规范和实现。
规格:
#ifndef UNSORTEDLIST_H
#define UNSORTEDLIST_H
#include <iostream>
using namespace std;
struct Node {
float element;
Node* next;
};
class UnsortedList
{
public:
UnsortedList();
bool IsEmpty();
bool IsFull();
void ResetList();
void MakeEmpty();
int LengthIs();
bool IsInTheList(float item);
void InsertItem(float item);
void DeleteItem(float item);
float GetNextItem();
private:
Node* data;
Node* currentPos;
int length;
};
#endif
和实现:
UnsortedList::UnsortedList()
{
length = 0;
data = NULL;
currentPos = NULL;
}
bool UnsortedList:: IsEmpty(){
if(length == 0)
{
return true;
}
else
{
return false;
}
}
bool UnsortedList::IsFull(){
Node* ptr = new Node();
if(ptr == NULL)
return true;
else
{
delete ptr;
return false;
}
}
void UnsortedList::ResetList(){
currentPos = NULL;
}
void UnsortedList::MakeEmpty()
{
Node* tempPtr = new Node();
while(data != NULL)
{
tempPtr = data;
data = data->next;
delete tempPtr;
}
length = 0;
}
int UnsortedList::LengthIs(){
return length;
}
bool UnsortedList:: IsInTheList(float item){
Node* location = new Node();
location = data;
bool found = false;
while(location != NULL && !found)
{
if(item == location->element)
found = true;
else
location = location->next;
}
return found;
}
void UnsortedList:: InsertItem(float item){
Node* location = new Node();
location->element = item;
location->next=data;
data = location;
length++;
}
void UnsortedList:: DeleteItem(float item){
Node* location = data;
Node* tempPtr;
if(item == data->element){
tempPtr = location;
data = data->next;
}
else{
while(!(item == (location->next) ->element) )
location = location->next;
tempPtr = location->next;
location->next = (location->next)->next;
}
delete tempPtr;
length--;
}
float UnsortedList::GetNextItem(){
if(currentPos == NULL)
currentPos = data;
else
currentPos = currentPos->next;
return currentPos->element;
}
1.在构造函数中,为什么不将currentPos赋值为null?
2.在IsInTheList函数中,为什么指向指针“next”?next 不是空指针,因为它已在 struct 中声明为 Node* next 吗?