java - 如何丢弃文本文件中的行，直到找到某个字符串

Question

该文件以大约 200 行我不需要的背景信息开头。我试图跳过/忽略这 200 行，直到找到一个字符串。找到此字符串后，我希望能够继续处理文本文件的其余部分。

示例文本文件：（直到第 240 行是我需要跳过/忽略的所有行） http://pastebin.com/5Ay4ad6y

public static void main(String args[]) {
    String endOfSyllabus = "~ End of Syllabus";
    Path objPath = Paths.get("2014HamTechnician.txt");

    if (Files.exists(objPath)) {
        File objFile = objPath.toFile();
        try (BufferedReader in = new BufferedReader(new FileReader(objFile))) {
            String line = in.readLine();

            while (line != null) {
                line = in.readLine();
            }

            if(endOfSyllabus.equals(line) ){

           restOfTextFile = line.split(endOfSyllabus);
         }

         }

        System.out.println(restOfTextFile[0]);




        }
    catch(IOException e){
          System.out.println(e);
    }

    }
    else{

        System.out.println(
              objPath.toAbsolutePath() + " doesn't exist");
    }



    /* Create and display the form */
    java.awt.EventQueue.invokeLater(new Runnable() {
        public void run() {
            new A19015_Form().setVisible(true);
        }
    });
}

Answer 1

关于什么：

boolean found = false;
for (String line; (line = in.readLine()) != null;) {
    found = found || line.equals(endOfSyllabus); 
    if (found) {
         // process line
    }
}

Answer 2

import java.io.File;
import java.io.IOException;
import java.util.ArrayList;
import java.util.List;

import org.apache.commons.io.FileUtils;

public class Test {

    /**
     * @param args
     * @throws IOException
     */
    public static void main(String[] args) throws IOException {
        List<String> lines = FileUtils.readLines(new File("test.txt"));
        List<String> avLines = new ArrayList<>();
        boolean valid = false;
        for (String line : lines) {

            if (line.trim().equals("~ End of Syllabus")) {
                valid = true;
                continue;
            }
            if (valid) {
                avLines.add("\n"+line);
            }
        }
        System.out.println(avLines.size());

    }

}

Answer 3

如果您知道要查找的确切字符串，则可以尝试此操作

if (lineString.startsWith("insert exact string")) {
    // ...
}