输入:
<Move-Afile>
<Afile>
<Item>
<suppliercode>1</suppliercode>
<PackNumber>1234</PackNumber>
<Item85>
<Quantity>12</Quantity>
</Item85>
</Item>
<Item>
<suppliercode>2</suppliercode>
<PackNumber>567</PackNumber>
<Item85>
<Quantity>3</Quantity>
</Item85>
</Item>
<Item>
<suppliercode>1</suppliercode>
<PackNumber>567</PackNumber>
<Item85>
<Quantity>8</Quantity>
</Item85>
</Item>
<Item>
<suppliercode>3</suppliercode>
<PackNumber>126</PackNumber>
<Item85>
<Quantity>11</Quantity>
</Item85>
</Item>
<Item>
<suppliercode>4</suppliercode>
<PackNumber>876</PackNumber>
<Item85>
<Quantity>32</Quantity>
</Item85>
</Item>
</Afile>
</Move-Afile>
xslt:
我需要像 xsl 这样的解决方案应该包含如下的 for-each 结构。
如果供应商代码相等,那么我们必须对这些节点的数量值求和,否则直接映射数量值。
<xsl:for-each select="/Move-Afile/Afile/Item">
<xsl:choose>
<xsl:when test="suppliercode=suppliercode>
<xsl:value-of select=sum(Quantity)"/><!-- sum of quantity where nodes have equal supplier code-->
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="Quantity"/><!-- map directly the quantity value-->
</xsl:otherwise>
</xsl:choose>
</xsl:for-each>
输出:
<A>
<target>
<Item>
<Quantity>20</Quantity>
</Item>
<Item>
<Quantity>3</Quantity>
</Item>
<Item>
<Quantity>20</Quantity>
</Item>
<Item>
<Quantity>11</Quantity>
</Item>
<Item>
<Quantity>32</Quantity>
</Item>
</target>
</A>