如何向 Twitter 引导导航栏链接显示 OpenCart 父类别?
我只想显示父类别,这是我的 HTML 标记
<ul class="nav" role="navigation">
<li class="dropdown" id="fat-menu">
<a data-toggle="dropdown" class="dropdown-toggle" role="button" id="drop3" href="#">Store<b class="caret"></b></a>
<ul aria-labelledby="drop3" role="menu" class="dropdown-menu">
<li role="presentation"><a href="#" tabindex="-1" role="menuitem">Shop Front</a></li>
<li class="divider" role="presentation"></li>
<li role="presentation"><a href="#" tabindex="-1" role="menuitem">Parent Category 1</a></li><!-- Show Parent Category Here -->
<li role="presentation"><a href="#" tabindex="-1" role="menuitem">Parent Category 2</a></li>
</ul>
</li>
</ul>
和我正在研究的当前标记和 PHP 代码......我试图复制 LI 但它给出了一个解析错误。
<?php if ($categories) { ?>
<div id="menu-holder" class="<?php echo (isset($styler['menu_style']) && ($styler['menu_style']!='')) ? $styler['menu_style']."_menu" : '' ;?>">
<div id="menu">
<ul>
<li><a href="<?php echo $home; ?>"><span class='home_icon'></span></a>
<?php foreach ($categories as $category) { ?>
<li><a href="<?php echo $category['href']; ?>"><?php echo $category['name']; ?><?php if ($category['children']) { ?><span></span><?php } ?></a>
<?php if ($category['children']) { ?>
<div>
<?php for ($i = 0; $i < count($category['children']);) { ?>
<ul>
<?php $j = $i + ceil(count($category['children']) / $category['column']); ?>
<?php for (; $i < $j; $i++) { ?>
<?php if (isset($category['children'][$i])) { ?>
<li><a<?php echo ($i==(count($category['children'])-1) ? " class='last_submenu_item'" : '');?> href="<?php echo $category['children'][$i]['href']; ?>"><span><?php echo $category['children'][$i]['name']; ?></span></a></li>
<?php } ?>
<?php } ?>
</ul>
<?php } ?>
</div>
<?php } ?>
</li>
<?php } ?>
</ul>
</div>
</div>
<?php } ?>