我想按当前日期计算来自不同表的记录,并在新表中作为具有不同列的一行返回。该代码将每三个小时更新一次记录,并在当前日期更改时插入新记录。我在“created_at”列中有当前日期和时间数据(2013-05-20 14:12:12)。这是我当前的代码:
require_once('./db_connect.php');
$dbcon = new db;
//test to see if a specific field value is already in the DB
public function in_table($table,$where) {
$query = 'SELECT * FROM ' . $table . ' WHERE ' . $where;
$result = mysqli_query($this->dbh,$query);
$this->error_test('in_table',$query);
return mysqli_num_rows($result) > 0;
}
//running in background
while (true) {
$select= "SELECT (SELECT CURDATE()) AS time," .
"(SELECT COUNT(tweet_id) FROM tweets WHERE created_at= 'CURDATE() %') AS total_count," .
"(SELECT COUNT(fid) FROM fun WHERE ftime= 'CURDATE() %') AS f_count," .
"(SELECT COUNT(sid) FROM sad WHERE stime= 'CURDATE() %') AS s_count";
$results = mysqli_query( $dbcon, $select );
while($row = mysqli_fetch_assoc($result)) {
$time = $row['time'];
$total = $row['total_count'];
$fcount = $row['f_count'];
$scount = $row['s_count'];
$field_values = 'time = "' . $time . '", ' . 'total_count = ' . $total . ', ' . 'fun_count = ' . $fcount . ', ' . 'sad_count = ' . $scount;
if ($dbcon->in_table('count','time= "' . $time . '"')) {
$update = "UPDATE count SET $field_values WHEN time= '$time'";
mysqli_query( $dbcon, $update );
}
else {
$insert = "INSERT INTO count SET $field_values";
mysqli_query( $dbcon, $insert );
}
}
//update record every 3 hour
sleep(10800);
}
使用此代码,我无法获得计数记录。结果返回| 2013-05-18 | 0 | 0 | 0 |
。我该如何纠正?