python - Python any() 方法结果

Question

我想知道以下结果将如何产生 True？

>>> x=['0']
>>> valid_diff=['0','1','2','3']
>>> result =any(x for each in x if x in valid_diff)
>>> result 
False

我希望结果为 True，因为第一个元素本身将为 True。

任何想法，我确定我在这里遗漏了一些东西..

Answer 1

你的变量名打错了，你应该检查if each in valid_diffnotif x in valid_diff和each for eachnotx for each

Answer 2

除了错字，我认为这里不需要存储each，只需使用：

#returns True if any item in x is found in valid_diff
>>> any(each in valid_diff for each in x)
True

或严格坚持您尝试做的事情然后使用它：

any(each in valid_diff and each for each in x)
#will return `True` only if any item found in valid_diff is a Truth value as well.

真值测试

Answer 3

正确的语法：

>>> result =any(each for each in x if each in valid_diff)