2

在我的代码中

public void vodKeyCtrl(byte[] sendDataByte, int send_length) {

    try {
        Log.i(TAG, addr.toString());
        InetAddress ia = InetAddress.getByName(addr.getKeyIp());
        DatagramSocket socket = new DatagramSocket(0);
        socket.connect(ia, addr.getKeyPort());
        DatagramPacket dp = new DatagramPacket(sendDataByte, sendDataByte.length);
        socket.send(dp);
        socket.setSendBufferSize(sendDataByte.length);
        socket.close();
    } catch (Exception e) {
        Log.e(TAG, e.toString());
    }
}

似乎没有错误和异常，它在 JAVA 应用程序上运行良好。虽然它不能在我的手机 i9300 上运行。我更改 AndroidManifest.xml 代码中的代码

 <uses-sdk
    android:minSdkVersion="8"
    android:targetSdkVersion="17" />

编码<uses-sdk android:minSdkVersion="8" android:targetSdkVersion="8" /> 它只是工作正常!!!我只是无法理解为什么会发生这种情况？任何人都可以帮助我吗？

4

1 回答 1

1

首先确保您的清单具有互联网许可

"使用权限 android:name="android.permission.INTERNET"

然后在 SDK8 之后你必须使用这样的线程

public class MainActivity extends Activity implements OnClickListener
{
public static final String DEST_IP = "192.168.1.7";
    public static final int DEST_UDP_PORT = 1234;
    public static final byte[] buf = {'H','e','l','l','o',' ','U','D','P'}; 
    public Button Send_UDP_Button;

    @Override
    protected void onCreate(Bundle savedInstanceState)
    {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);

        Send_UDP_Button = (Button)findViewById(R.id.button1); 
        Send_UDP_Button.setOnClickListener(this); 
    }

    @Override
    public void onClick(View v)
    {
        new Thread(new Client()).start();
    }

    public class Client implements Runnable
    { 
        @Override 
        public void run()
        { 
            try
            { 
                InetAddress serverAddr = InetAddress.getByName(DEST_IP); 
                DatagramSocket socket = new DatagramSocket(); 
                DatagramPacket packet = new DatagramPacket(buf, buf.length, serverAddr, DEST_UDP_PORT); 
                socket.send(packet); 
                socket.close(); 
            }
            catch (Exception e)
            { 
                Log.w("Too Bad",e);
            } 
        } 
    } 
}

我希望这个能帮上忙 ！抱歉不能投票支持你的问题，我没有足够的声誉！:-(

于 2013-06-28T04:55:08.420 回答