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我一直在审查一些例子，但我没有找到我需要的东西。这是一个查询，显示按月分组的每个代理机构的记录计数。这是我的表结构的一部分：

recid | agency_id | departure_date

所以我需要按机构和月份（出发日期）计算“recid”组并获得总列

  Agency_id  | JAN | FEB | MAR | APR | MAY | ........ | TOTAL 

      10        100  80    100   120   100    1200

这似乎很容易。但我找不到解决方案。任何帮助将不胜感激！！！

4

4 回答 4

1

尝试

SELECT agency_id, 
       SUM(CASE WHEN MONTH(departure_date) = 1 THEN 1 ELSE 0 END) Jan,
       SUM(CASE WHEN MONTH(departure_date) = 2 THEN 1 ELSE 0 END) Feb,
       SUM(CASE WHEN MONTH(departure_date) = 3 THEN 1 ELSE 0 END) Mar,
       ...
       COUNT(*) Total
  FROM table1
 WHERE departure_date BETWEEN '2013-01-01' AND '2013-12-31'
 GROUP BY agency_id

输出：

| AGENCY_ID | JAN | FEB | MAR | APR | MAY | JUN | JUL | AUG | SEP | OCT | NOV | DEC | TOTAL |
---------------------------------------------------------------------------------------------
|         1 |   1 |   1 |   1 |   0 |   0 |   0 |   0 |   0 |   0 |   0 |   0 |   0 |     3 |
|         2 |   2 |   2 |   1 |   0 |   0 |   0 |   0 |   0 |   0 |   0 |   0 |   0 |     5 |
|         3 |   0 |   0 |   2 |   0 |   0 |   0 |   0 |   0 |   0 |   0 |   0 |   0 |     2 |

SQLFiddle

于 2013-05-20T04:19:33.490 回答
0

看看这个带有 ROLLUP 子句的解决方案，它显示了你需要什么，但给出了另一个输出 -

SELECT
  agency_id, MONTH(departure_date) month, COUNT(*) count
FROM
  sales
GROUP BY
  agency_id, MONTH(departure_date) WITH ROLLUP
WHERE
  YEAR(departure_date) = 2013
于 2013-05-20T06:26:06.087 回答
0

尝试

 select agency_id, 
    sum(if(month(`departure_date`) = 1,1,0)) as 'JAN',
    sum(if(month(`departure_date`) = 2,1,0)) as 'FEB',
    sum(if(month(`departure_date`) = 3,1,0)) as 'MAR',
    sum(if(month(`departure_date`) = 4,1,0)) as 'APR',
    sum(if(month(`departure_date`) = 5,1,0)) as 'MAY',
    sum(if(month(`departure_date`) = 6,1,0)) as 'JUN',
    sum(if(month(`departure_date`) = 7,1,0)) as 'JULY',
    sum(if(month(`departure_date`) = 8,1,0)) as 'AUG',
    sum(if(month(`departure_date`) = 9,1,0)) as 'SEPT',
    sum(if(month(`departure_date`) = 10,1,0)) as 'OCT',
    sum(if(month(`departure_date`) = 11,1,0)) as 'NOV',
    sum(if(month(`departure_date`) = 12,1,0)) as 'DEC',
            count(agency_id) as TOTAL 
 from tablename
 where .....
 group by agency_id
于 2013-05-20T04:19:16.797 回答
0

试试这个：

SELECT 
    agency_id,
    SUM(IF(month = 1, numRecords, NULL)) AS 'January',
    SUM(IF(month = 2, numRecords, NULL)) AS 'Feburary',
    SUM(IF(month = 3, numRecords, NULL)) AS 'March',
    SUM(IF(month = 4, numRecords, NULL)) AS 'April',
    SUM(IF(month = 5, numRecords, NULL)) AS 'May',
    SUM(IF(month = 6, numRecords, NULL)) AS 'June',
    SUM(IF(month = 7, numRecords, NULL)) AS 'July',
    SUM(IF(month = 8, numRecords, NULL)) AS 'August',
    SUM(IF(month = 9, numRecords, NULL)) AS 'September',
    SUM(IF(month = 10, numRecords, NULL)) AS 'October',
    SUM(IF(month = 11, numRecords, NULL)) AS 'November',
    SUM(IF(month = 12, numRecords, NULL)) AS 'December',
    SUM(numRecords) AS total
    FROM (
        SELECT agency_id, month(departure_date) AS month, count(*) as numRecords
        FROM your_table_name
        GROUP BY agency_id, month
    ) AS SubTable1 GROUP BY agency_id

对于特定机构 ID 不存在记录的月份，此查询将显示null。如果要将其显示为0，请更新查询并将 替换NULL为文字0。

于 2013-05-20T04:32:01.220 回答