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基本上,每次按下 F1 键时,我都会尝试切换布尔值。在我的主课中,我有每秒调用 60 次的更新方法,我编写了如下代码:

主类:

private Keyboard key = new Keyboard; // keyboard object
boolean debug; // boolean to control visibility of debug screen
private boolean toggle; // used to toggle boolean

private void update() { // update is called 60/s
    if (key.isKeyPressed(Keyboard.f1) && !toggle) {
        debug = !debug;
        toggle = true;
    } else if (!key.isKeyPressed(Keyboard.f1)) toggle = false;
}

键盘类:

public class Keyboard implements KeyListener {

private boolean[] keys = new boolean[65536];

public static final int f1 = KeyEvent.VK_F1; // key code of f1 key

public void keyPressed(KeyEvent e) {
    keys[e.getKeyCode()] = true;
}

public void keyReleased(KeyEvent e) {
    keys[e.getKeyCode()] = false;
}

public void keyTyped(KeyEvent e) {
}

public boolean isKeyPressed(int key) {
    return keys[key];
}

这样它就可以完美运行,但是如果我在 Keyboard.class 中创建类似的方法,它就不起作用:

主类中的更新方法:

private void update() {
    key.toggle(Keyboard.f1, debug); // toggle boolean debug if f1 key pressed, but.. NOT WORKING!! WHYYY!!?
}

键盘类:

private boolean toggle;

public void toggle(int key, boolean b) {
    if (isKeyPressed(key) && !toggle) {
        b = !b;
        toggle = true;
    } else if (!isKeyPressed(key)) toggle = false;
}

我的问题是: 为什么第二种方法不起作用,我该如何解决它? 谢谢!

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1 回答 1

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谢谢MadProgrammer,你是对的!;D

主类:

private void update() {
    debug = key.toggle(Keyboard.f1, debug); 
}

键盘类:

private boolean toggle;

public boolean toggle(int key, boolean b) {
    if (isKeyPressed(key) && !toggle) {
        b = !b;
        toggle = true;
    } else if (!isKeyPressed(key) && toggle) {
        toggle = false;
    }
    return b;
}

现在它返回了我想要的值,谢谢,我完全忘记了这一点。有没有更好/更简单的方法来做到这一点?

于 2013-05-20T09:53:32.227 回答