bash - Echo and backslash (bash)

Question

I'm trying to make a function in my ~/.bashrc file that uses an echo command to pass its arguments through the pipeline. It works, but when I try to input a '\' character it disappears. If I type \\ (two '\') it succeeds. This heppens even with -E option...

So, how can I make the code below prints "foo\bar" instead of "foobar"?

func()
{
    echo -E "${@}"
}

Answer 1

不是echo解释反斜杠的人，而是shell。它甚至在你的函数被调用之前就被解释了。正确的解决方案是引用函数的参数。

func()
{
    echo -E "${@}"
}

func 'foo\bar'

Answer 2

您需要确保您确实为函数提供了反斜杠；该函数本身工作正常，如： jlaiho@LT2:~$ fun() { echo -E "$@"; }
jlaiho@LT2:~$ fun 'foo\bar'
foo\bar

然而，如果反斜杠甚至没有到达函数，它就不会被打印出来：
jlaiho@LT2:~$ fun foo\bar
foobar