awk - Using sed to delete range of lines except the end pattern

Question

input.txt:

blah1
blah2
start_pattern
blah3
blah4
blah5
end_pattern
blah6
blah7

I would like input.txt to become:

blah1
blah2
end_pattern
blah6
blah7

I tried the following, but it didn't work.

sed -i "/start_pattern/, /end_pattern/{$!d}" input.txt

Answer 1

这个问题涉及您的问题：

$ sed '/start_pattern/,/end_pattern/{/end_pattern/!d}' foo.txt
blah1
blah2
end_pattern
blah6
blah7

Answer 2

sed 是在单行上进行简单替换的出色工具。对于任何其他文本操作，只需使用 awk 即可获得更清晰、更简单、更易于扩展的解决方案：

$ awk '/start_pattern/{f=1} /end_pattern/{f=0} !f;' file
blah1
blah2
end_pattern
blah6
blah7

也可以看看：

$ awk '/start_pattern/{f=1} !f; /end_pattern/{f=0}' file
blah1
blah2
blah6
blah7

$ awk '!f; /start_pattern/{f=1} /end_pattern/{f=0}' file
blah1
blah2
start_pattern
blah6
blah7

$ awk '/start_pattern/{f=1} /end_pattern/{f=0} f;' file
start_pattern
blah3
blah4
blah5

$ awk '/start_pattern/{f=1} f; /end_pattern/{f=0}' file
start_pattern
blah3
blah4
blah5
end_pattern

$ awk 'f; /start_pattern/{f=1} /end_pattern/{f=0}' file
blah3
blah4
blah5
end_pattern