0

我正在使用 API 来显示某个地点的位置详细信息。但是我也无法显示地图。当我尝试调试 java 脚本时，出现参考错误

 service.getDetails()

我想在标记的单击事件中的信息窗口中显示位置详细信息。任何人都可以帮我解决这个问题。这是我的代码

function initialize() {
var map = new google.maps.Map(document.getElementById('map-canvas'), {
mapTypeId: google.maps.MapTypeId.ROADMAP,
center: new google.maps.LatLng(-33.8665433, 151.1956316),
zoom: 15
});

var request = {
reference: 'CnRkAAAAGnBVNFDeQoOQHzgdOpOqJNV7K9-c5IQrWFUYD9TNhUmz5-  aHhfqyKH0zmAcUlkqVCrpaKcV8ZjGQKzB6GXxtzUYcP-muHafGsmW-1CwjTPBCmK43AZpAwW0FRtQDQADj3H2bzwwHVIXlQAiccm7r4xIQmjt_Oqm2FejWpBxLWs3L_RoUbharABi5FMnKnzmRL2TGju6UA4k'
};

var infowindow = new google.maps.InfoWindow();
var service = new google.maps.places.PlacesService(map);

service.getDetails(request, function(place, status) {
if (status == google.maps.places.PlacesServiceStatus.OK) {
  var marker = new google.maps.Marker({
    map: map,
    position: place.geometry.location
  });
  google.maps.event.addListener(marker, 'click', function() {
    infowindow.setContent(place.name);
    infowindow.open(map, this);
  });
}
 });
  }
4

2 回答 2

0

地点引用仅在会话中有效。您无法保存字符串并再次使用它。

var request =  {
      reference: place.reference
};
google.maps.event.addListener(marker,'click',function(){
    service.getDetails(request, function(place, status) {
      if (status == google.maps.places.PlacesServiceStatus.OK) {
        var contentStr = '<h5>'+place.name+'</h5><p>'+place.formatted_address;
        if (!!place.formatted_phone_number) contentStr += '<br>'+place.formatted_phone_number;
        if (!!place.website) contentStr += '<br><a target="_blank" href="'+place.website+'">'+place.website+'</a>';
        contentStr += '<br>'+place.types+'</p>';
        infowindow.setContent(contentStr);
        infowindow.open(map,marker);
      } else { 
        var contentStr = "<h5>No Result, status="+status+"</h5>";
        infowindow.setContent(contentStr);
        infowindow.open(map,marker);
      }
    });

例子

于 2013-05-17T13:40:06.740 回答
0

您需要在请求中明确加载此库；

https://maps.googleapis.com/maps/api/js?libraries=places&key=yourApiKey

于 2013-05-17T11:40:23.957 回答