4

我有类似使用fputcsv创建的字符串

Date,Name,Hours 2013-01-02,"Test User",7:59 2013-01-03,"Test User",7:53 2013-01-04,"Test User",8:12 2013-01-07,"Test User",7:56 2013-01-08,"Test User",8:25 2013-01-09,"Test User",7:56 2013-01-10,"Test User",8:10 2013-01-11,"Test User",7:53 2013-01-14,"Test User",7:54 2013-01-15,"Test User",0:34 2013-04-01,"Test User",5:51 2013-04-02,"Test User",8:50 2013-04-03,"Test User",7:25 2013-04-04,"Test User",8:3 2013-04-05,"Test User","10:42:52[Not punch out]" ,Total,103:1

当设置正确的标题 (header('Content-type: application/csv'); header('Content-Disposition: attachment; filename="'.$filename.'"');) 时,它会提供正确的 csv 文件。

使用 php str_getcsv 将 csv 文件数据转换为数组

但是我希望再次将此字符串转换为数组格式,所以我尝试将上面的字符串传递给str_getcsv但得到这样的数组

Array
(
    [0] => Date
    [1] => Name
    [2] => Hours
2013-01-02
    [3] => "Allen Herrera"
    [4] => 7:59
2013-01-03
    [5] => "Allen Herrera"
    [6] => 7:53
2013-01-04
    [7] => "Allen Herrera"
    [8] => 8:12
2013-01-07
    [9] => "Allen Herrera"
    [10] => 7:56
2013-01-08
    [11] => "Allen Herrera"
    [12] => 8:25
2013-01-09
    [13] => "Allen Herrera"
    [14] => 7:56
2013-01-10
    [15] => "Allen Herrera"
    [16] => 8:10
2013-01-11
    [17] => "Allen Herrera"
    [18] => 7:53
2013-01-14......................

您能帮我获得正确格式化的数组,以便我可以轻松地使用它在数组上创建表循环。

4

5 回答 5

5
 $file = file_get_contents("test.csv");
 $data = array_map("str_getcsv", preg_split('/\r*\n+|\r+/', $file));
 print_r($data);
于 2013-05-17T11:43:03.117 回答
3

经过一番搜索后得到了解决方案

$data = array_map("str_getcsv", preg_split('/\r*\n+|\r+/', $string_data));
print_r($data);

给我这样的数组

Array
(
    [0] => Array
        (
            [0] => Date
            [1] => Name
            [2] => Hours
        )

    [1] => Array
        (
            [0] => 2013-01-02
            [1] => Test User
            [2] => 7:59
        )

    [2] => Array
        (
            [0] => 2013-01-03
            [1] => Test User
            [2] => 7:53
        )

    [3] => Array
        (
            [0] => 2013-01-04
            [1] => Test User
            [2] => 8:12
        )

    [4] => Array
        (
            [0] => 2013-01-07
            [1] => Test User
            [2] => 7:56
        )

    [5] => Array
        (
            [0] => 2013-01-08
            [1] => Test User
            [2] => 8:25
        )

    [6] => Array
        (
            [0] => 2013-01-09
            [1] => Test User
            [2] => 7:56
        )

    [7] => Array
        (
            [0] => 2013-01-10
            [1] => Test User
            [2] => 8:10
        )...
于 2013-05-17T11:35:38.943 回答
2

这将是这样的:

$parts = explode(PHP_EOL, $string);
$array = array();
foreach ($parts as $part) {
    $array[] = str_getcsv($part);
}

print_r($array);
于 2013-05-17T11:35:43.507 回答
2

我使用这种方式将 csv 文件数据转换为数组:-

ini_set('auto_detect_line_endings', TRUE);/// (PHP's detection of line endings) write at the top.


$csvrows = array_map('str_getcsv', file($filepath));
$csvheader = array_shift($csvrows);
$csv = array();
foreach ($csvrows as $row) {
   $csv[] = array_combine($csvheader, $row);
}
于 2014-12-13T06:43:25.433 回答
-1
 $path = 'uploads/my_csvfile.csv';
 $file_content = file_get_contents($path);
 $matches = array_map('str_getcsv', preg_split('/\r*\n+|\r+/',$file_content));
 print_r($matches);
于 2016-02-20T05:23:51.570 回答