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如何解决以下编译器错误：

xstddef(180): error C2678: binary '<' : no operator found which takes a left-hand operand of type 'const std::string' (or there is no acceptable conversion)
          tuple(572): could be 'bool std::operator <(const std::tuple<> &,const std::tuple<> &)'
          while trying to match the argument list '(const std::string, const std::string)'
          xstddef(179) : while compiling class template member function 'bool std::less<_Ty>::operator ()(const _Ty &,const _Ty &) const'
          with
          [
              _Ty=std::string
          ]
          map(177) : see reference to function template instantiation 'bool std::less<_Ty>::operator ()(const _Ty &,const _Ty &) const' being compiled
          with
          [
              _Ty=std::string
          ]
          type_traits(743) : see reference to class template instantiation 'std::less<_Ty>' being compiled
          with
          [
              _Ty=std::string
          ]
          xtree(1028) : see reference to class template instantiation 'std::is_empty<_Ty>' being compiled
          with
          [
              _Ty=std::less<std::string>
          ]
          map(67) : see reference to class template instantiation 'std::_Tree<_Traits>' being compiled
          with
          [
              _Traits=std::_Tmap_traits<std::string,IDispatcherPtr,std::less<std::string>,std::allocator<std::pair<const std::string,IDispatcherPtr>>,false>
          ]
          main.cpp(506) : see reference to class template instantiation 'std::map<_Kty,_Ty>' being compiled
          with
          [
              _Kty=std::string,
              _Ty=IDispatcherPtr
          ]

对于以下代码：

class IDispatcher
{
    virtual void operator()() = 0;
};

class AlarmDispatcher: public IDispatcher
{
    virtual void operator()()
    {
    }
};

typedef boost::shared_ptr<IDispatcher> IDispatcherPtr;

int main()
{
    std::map<std::string, IDispatcherPtr> dispatchers;
    dispatchers["alarm"] = boost::make_shared<AlarmDispatcher>();
4

2 回答 2

5

第一个问题：

您应该明确包含所有必要的标头，而不是依赖于通过包含其他标头来间接包含它们：

#include <string> // <== IN PARTICULAR THIS ONE
#include <map>
#include <boost/shared_ptr.hpp>
#include <boost/make_shared.hpp>

从评论来看，您似乎包含了<string.h>标头（这是标准 C 库标头）而不是<string>标头，这std::string是定义类的位置。

第二个问题：

您忘记建立类之间的继承关系：

class AlarmDispatcher : public IDispatcher
//                    ^^^^^^^^
{
    virtual void operator()()
    {
    }
};
于 2013-05-17T11:05:48.057 回答
0

对于将来遇到此问题的人：我通过在函数定义的末尾添加 const 来解决它，我用它来使类可用作 c++ std map 集合中的键：

bool operator <(const ThisClass& otherInstance)

变成：

bool operator <(const ThisClass& otherInstance) const
于 2016-08-11T04:51:15.527 回答