0

我使用 jqGrid 和 will_paginate 来制作表格。这是我在控制器中的代码

def index
  index_columns ||= [:pid,:name,:gender,:birthday,:school]
  current_page = params[:page] ? params[:page].to_i : 1
  rows_per_page = params[:rows] ? params[:rows].to_i : 10

  conditions={:page => current_page, :per_page => rows_per_page}
  conditions[:order] = params["sidx"] + " " + params["sord"] unless (params[:sidx].blank? || params[:sord].blank?)

  if params[:_search] == "true"
    conditions[:conditions]=filter_by_conditions(index_columns)
  end

  @people = Person.paginate(conditions)
  total_entries=@people.total_entries

  respond_with(@people) do |format|
    format.html
    format.json { render :json => @people.to_jqgrid_json(index_columns, current_page, rows_per_page, total_entries)}  
  end
end

使用这些代码,可以在 jqGrid 中正确排序和搜索数据。但是,在我将其修改为

  @temp = Person.limit(0).all
  KlassesPeople.where(:klass_id => 1).each do |stu|
    @temp.concat( Person.where(:id => stu.person_id) )
  end

  @people = @temp.paginate(conditions)
  total_entries=@people.total_entries

数据仍然可以在 jqGrid 中显示,但不能排序和搜索我确实在我的控制器中添加了 require 'will_paginate/array'

任何想法?

4

1 回答 1

0

I have uploaded jqgrid server side search and CRUD operation using ruby on rails 4.0

find the below link -

https://github.com/Rameshwar007/jqgrid_rails_4_sample

Let me know If you any further query.

于 2013-10-16T11:28:51.587 回答