我想知道，是否可以偏移径向轴的起点或将其移出图形。
这是我希望实现的目标：
这就是我现在所拥有的。
我已经阅读了关于 SO 的文档和不同的主题，但我找不到任何有用的东西。这是否意味着如果没有在任何地方提及它甚至是不可能的。
先感谢您。
编辑（添加了用于创建绘图的代码片段）：
ax = fig.add_subplot(111, projection='polar')
ax.set_theta_zero_location('N')
ax.set_theta_direction(-1)
ax.plot(X,lines[li]*yScalingFactor,label=linelabels[li],color=color,linestyle=ls)
我不确定是否polar plot可以这样调整。但这里有一个变通方法，基于此处给出的最后一个示例：浮动轴。
我在代码中包含了解释性注释，如果您复制/粘贴它，它应该按原样运行：
import mpl_toolkits.axisartist.floating_axes as floating_axes
from matplotlib.projections import PolarAxes
from mpl_toolkits.axisartist.grid_finder import FixedLocator, \
MaxNLocator, DictFormatter
import numpy as np
import matplotlib.pyplot as plt
# generate 100 random data points
# order the theta coordinates
# theta between 0 and 2*pi
theta = np.random.rand(100)*2.*np.pi
theta = np.sort(theta)
# "radius" between 0 and a max value of 40,000
# as roughly in your example
# normalize the r coordinates and offset by 1 (will be clear later)
MAX_R = 40000.
radius = np.random.rand(100)*MAX_R
radius = radius/np.max(radius) + 1.
# initialize figure:
fig = plt.figure()
# set up polar axis
tr = PolarAxes.PolarTransform()
# define angle ticks around the circumference:
angle_ticks = [(0, r"$0$"),
(.25*np.pi, r"$\frac{1}{4}\pi$"),
(.5*np.pi, r"$\frac{1}{2}\pi$"),
(.75*np.pi, r"$\frac{3}{4}\pi$"),
(1.*np.pi, r"$\pi$"),
(1.25*np.pi, r"$\frac{5}{4}\pi$"),
(1.5*np.pi, r"$\frac{3}{2}\pi$"),
(1.75*np.pi, r"$\frac{7}{4}\pi$")]
# set up ticks and spacing around the circle
grid_locator1 = FixedLocator([v for v, s in angle_ticks])
tick_formatter1 = DictFormatter(dict(angle_ticks))
# set up grid spacing along the 'radius'
radius_ticks = [(1., '0.0'),
(1.5, '%i' % (MAX_R/2.)),
(2.0, '%i' % (MAX_R))]
grid_locator2 = FixedLocator([v for v, s in radius_ticks])
tick_formatter2 = DictFormatter(dict(radius_ticks))
# set up axis:
# tr: the polar axis setup
# extremes: theta max, theta min, r max, r min
# the grid for the theta axis
# the grid for the r axis
# the tick formatting for the theta axis
# the tick formatting for the r axis
grid_helper = floating_axes.GridHelperCurveLinear(tr,
extremes=(2.*np.pi, 0, 2, 1),
grid_locator1=grid_locator1,
grid_locator2=grid_locator2,
tick_formatter1=tick_formatter1,
tick_formatter2=tick_formatter2)
ax1 = floating_axes.FloatingSubplot(fig, 111, grid_helper=grid_helper)
fig.add_subplot(ax1)
# create a parasite axes whose transData in RA, cz
aux_ax = ax1.get_aux_axes(tr)
aux_ax.patch = ax1.patch # for aux_ax to have a clip path as in ax
ax1.patch.zorder=0.9 # but this has a side effect that the patch is
# drawn twice, and possibly over some other
# artists. So, we decrease the zorder a bit to
# prevent this.
# plot your data:
aux_ax.plot(theta, radius)
plt.show()
这将生成以下图：
您必须调整轴标签以满足您的需求。
我缩放了数据，因为否则会发生与您的绘图相同的问题 - 内部的空圆圈将被缩放为一个点。您可以尝试使用极坐标图进行缩放，只需将自定义标签放在径向轴上即可达到类似的效果。
要偏移径向轴的起点：
编辑：从 Matplotlib 2.2.3 开始，有一个新的 Axes 方法set_rorigin可以做到这一点。你用原点的理论径向坐标来调用它。因此，如果您调用ax.set_ylim(0, 2)and ax.set_rorigin(-1)，中心圆的半径将是绘图半径的三分之一。
Matplotlib < 2.2.3 的一个快速而肮脏的解决方法是将径向轴下限设置为负值并将绘图的内部隐藏在一个圆圈后面：
import numpy as np
import matplotlib.pyplot as plt
CIRCLE_RES = 36 # resolution of circle inside
def offset_radial_axis(ax):
x_circle = np.linspace(0, 2*np.pi, CIRCLE_RES)
y_circle = np.zeros_like(x_circle)
ax.fill(x_circle, y_circle, fc='white', ec='black', zorder=2) # circle
ax.set_rmin(-1) # needs to be after ax.fill. No idea why.
ax.set_rticks([tick for tick in ax.get_yticks() if tick >= 0])
# or set the ticks manually (simple)
# or define a custom TickLocator (very flexible)
# or leave out this line if the ticks are fully behind the circle
要在绘图外添加比例：
您可以在其他轴的上半部分添加一个额外的轴对象并使用它的 yaxis：
X_OFFSET = 0 # to control how far the scale is from the plot (axes coordinates)
def add_scale(ax):
# add extra axes for the scale
rect = ax.get_position()
rect = (rect.xmin-X_OFFSET, rect.ymin+rect.height/2, # x, y
rect.width, rect.height/2) # width, height
scale_ax = ax.figure.add_axes(rect)
# hide most elements of the new axes
for loc in ['right', 'top', 'bottom']:
scale_ax.spines[loc].set_visible(False)
scale_ax.tick_params(bottom=False, labelbottom=False)
scale_ax.patch.set_visible(False) # hide white background
# adjust the scale
scale_ax.spines['left'].set_bounds(*ax.get_ylim())
# scale_ax.spines['left'].set_bounds(0, ax.get_rmax()) # mpl < 2.2.3
scale_ax.set_yticks(ax.get_yticks())
scale_ax.set_ylim(ax.get_rorigin(), ax.get_rmax())
# scale_ax.set_ylim(ax.get_ylim()) # Matplotlib < 2.2.3
把它们放在一起：
（示例取自Matplotlib 极坐标图演示）
r = np.arange(0, 2, 0.01)
theta = 2 * np.pi * r
ax = plt.subplot(111, projection='polar')
ax.plot(theta, r)
ax.grid(True)
ax.set_rorigin(-1)
# offset_radial_axis(ax) # Matplotlib < 2.2.3
add_scale(ax)
ax.set_title("A line plot on an offset polar axis", va='bottom')
plt.show()
