php - php 将今天的日期与（多维）数组中的日期进行比较？

Question

我有一个日期数组，我想知道是否可以搜索一个数组并删除今天日期之前的任何项目，并保留其余的？

这是我的数组

Array
(
    [0] => Array
        (
            [date] => 2013-07-14
        )

    [1] => Array
        (
            [date] => 2013-08-31
        )

    [2] => Array
        (
            [date] => 2013-09-15
        )

    [3] => Array
        (
            [date] => 2013-10-12
        )

    [4] => Array
        (
            [date] => 2013-10-16
        )

    [5] => Array
        (
            [date] => 2013-10-19
        )

    [6] => Array
        (
            [date] => 2013-10-23
        )

    [7] => Array
        (
            [date] => 2013-10-26
        )

    [8] => Array
        (
            [date] => 2013-10-30
        )

    [9] => Array
        (
            [date] => 2013-09-07
        )

    [10] => Array
        (
            [date] => 2013-08-14
        )

    [11] => Array
        (
            [date] => 2013-08-24
        )

    [12] => Array
        (
            [date] => 2013-09-11
        )

    [13] => Array
        (
            [date] => 2013-09-28
        )

    [14] => Array
        (
            [date] => 2013-10-05
        )

)

Answer 1

像这样的东西：

$buffer = array();
foreach ($dates as $element) {
    if (strtotime($element['date']) >= time()) {
        $buffer[] = $element;
    }
}

Answer 2

循环遍历并将日期与实际所需数据进行比较并构建一个新的过滤数组怎么样？

$newarray = array();
foraeach($array as $data)
{
     if($data['date'] >= $yourdate)
     {
         $newarray] = $data;
     }
}

Answer 3

array_walk函数允许您定义一个回调以在数组中的每个项目上运行。