我最近发现我们可以使用 Oracle 的 Max ( Decode ()) 函数来透视表的结果。我执行得很好。但是,旋转表格只是我需要的解决方案的一部分。旋转函数的结果如下:
01,02,03,05,06,07,08,09,10,11,12,13,14,16,17,20,21,23,25
我真正需要的是这样的:
1-17, 20-21,23,25
我真的不知道如何开始解决这个问题,但到目前为止我有以下查询:
SELECT DISTINCT
MAX(DECODE(wldw.wafernumber,'01', '01'))
|| MAX(DECODE(wldw.wafernumber,'02', ',02'))
|| MAX(DECODE(wldw.wafernumber,'03', ',03'))
|| MAX(DECODE(wldw.wafernumber,'04', ',04'))
|| MAX(DECODE(wldw.wafernumber,'05', ',05'))
|| MAX(DECODE(wldw.wafernumber,'06', ',06'))
|| MAX(DECODE(wldw.wafernumber,'07', ',07'))
|| MAX(DECODE(wldw.wafernumber,'08', ',08'))
|| MAX(DECODE(wldw.wafernumber,'09', ',09'))
|| MAX(DECODE(wldw.wafernumber,'10', ',10'))
|| MAX(DECODE(wldw.wafernumber,'11', ',11'))
|| MAX(DECODE(wldw.wafernumber,'12', ',12'))
|| MAX(DECODE(wldw.wafernumber,'13', ',13'))
|| MAX(DECODE(wldw.wafernumber,'14', ',14'))
|| MAX(DECODE(wldw.wafernumber,'15', ',15'))
|| MAX(DECODE(wldw.wafernumber,'16', ',16'))
|| MAX(DECODE(wldw.wafernumber,'17', ',17'))
|| MAX(DECODE(wldw.wafernumber,'18', ',18'))
|| MAX(DECODE(wldw.wafernumber,'19', ',19'))
|| MAX(DECODE(wldw.wafernumber,'20', ',20'))
|| MAX(DECODE(wldw.wafernumber,'21', ',21'))
|| MAX(DECODE(wldw.wafernumber,'22', ',22'))
|| MAX(DECODE(wldw.wafernumber,'23', ',23'))
|| MAX(DECODE(wldw.wafernumber,'24', ',24'))
|| MAX(DECODE(wldw.wafernumber,'25', ',25')) AS WAFERS
, 'history' as well
FROM a_wiplothistory wl
JOIN Container C ON (wl.containerid = c.containerid OR wl.containerid= c.splitfromid )
JOIN a_wiplotdetailshistory wld ON wl.wiplothistoryid = wld.wiplothistoryid
JOIN a_wiplotdetailswafershistory wldw ON wld.wiplotdetailshistoryid = wldw.wiplotdetailshistoryid
WHERE c.containername = :lot
感谢您的帮助。