c++ - 声明 Get Method const 时出现 C++ 错误

Question

C++中的const问题...

MyVektor[i].getName().getFirstName()产生错误：（见下面的代码）

Error 1 error C2662: 'Name::getFirstName' : cannot convert 'this' pointer from 'const Name' to 'Name &' c:\users\betula\documents\visual studio 2012\projects\c++laboration_2\c++laboration_2\person_test.cpp   215 1   C++Laboration_2

和

3   IntelliSense: the object has type qualifiers that are not compatible with the member function
            object type is: const Name  c:\Users\Betula\Documents\Visual Studio 2012\Projects\C++Laboration_2\C++Laboration_2\Person_Test.cpp   215 17  C++Laboration_2

main来自in PersonTest...的向量和方法调用

vector<Person> MyPersons;

ShowPerson(MyVektor);

方法：

void ShowPerson(vector<Person> &MyVektor)
{
cout << endl << " List of people: " << endl << endl;

for( size_t i = 0; i < MyVektor.size(); i++)
{
cout << " " + MyVektor[i].getName().getFirstName() + " " + MyVektor[i].getName().getLastName() << endl;

    //cout << " " + MyVektor[i].getAddress() + " " + MyVektor[i].getAddress()+ " " +     MyVektor[i].getAddress() << endl;

    cout <<" Social security number: " + MyVektor[i].getPersNr() << endl;

    cout <<" Shoe size: " + to_string(MyVektor[i].getSkoNr()) << endl << endl;  
    }
}

所有 Getmethods 都声明为 const i 类 Person & Name

const Name Person::getName()
{
return my_name;
}

const string Name::getFirstName()
{
return firstName;
}

如果我删除类 Person & Name 中的 const 声明一切正常......

对初学者有什么建议...

/尼莫斯

Answer 1

替换const Name Person::getName()为Name Person::getName() constetc. 以使函数保持不变，而不是返回变量。